What is the coefficient of static friction between the ladderand the f

Click For Summary
SUMMARY

The discussion focuses on calculating the coefficient of static friction required to prevent a ladder from slipping when a painter is positioned 70% up the ladder. The ladder has a mass of 12 kg, and the painter weighs 60 kg. The wall is frictionless, and the center of rotation can be chosen at any point, though it is typically convenient to select the base of the ladder for torque calculations. The key takeaway is that the problem can be reformulated to determine the minimum coefficient of friction necessary to maintain stability.

PREREQUISITES
  • Understanding of static equilibrium and torque principles
  • Knowledge of forces acting on inclined objects
  • Familiarity with the concept of coefficients of friction
  • Basic skills in solving statics problems
NEXT STEPS
  • Calculate the torque about the base of the ladder to find the coefficient of static friction
  • Explore the implications of frictionless surfaces in statics problems
  • Study the effects of varying the position of the painter on the ladder's stability
  • Learn about the role of center of mass in static equilibrium scenarios
USEFUL FOR

Students in physics, engineers working on statics problems, and anyone interested in understanding the mechanics of ladders and friction in real-world applications.

Link
Messages
132
Reaction score
1
Okay this one is really starting to get on my nerves. Drawing in the attachment.


Mass of ladder is 12kg. Mass of painter is 60kg. The ladder begins to slip when the person is 70percent up the ladder. The wall is frictionless.

What is the coefficient of static friction between the ladderand the floor?


I am unsure about where i should set the axis of torque, at the painter, the CM of the ladder or the wall?
 

Attachments

  • problem2.JPG
    problem2.JPG
    14.5 KB · Views: 490
Physics news on Phys.org
Since the ladder would rotate,what is the center of rotation??

Daniel.
 
Dex's answer is technically correct, but a bit misleading. You could pick anywhere that you like as the center of rotation because this is esentially a statics problem. Just make sure that you're calculating all of the torques about that point. Typically, people will chose a point that makes the calculation convenient like a location where many forces are applied - for example, the base of the ladder.

This problem can be rephrased as "what is the minimum coeficient of friction necessary to keep the ladder from slipping when the painter is 70% up the ladder?"
 

Similar threads

Replies
6
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
Replies
13
Views
7K
Replies
8
Views
1K
Replies
9
Views
2K
  • · Replies 42 ·
2
Replies
42
Views
5K
Replies
13
Views
2K
Replies
5
Views
2K