Solving Timescales Physics Problems: Timesteps and Normal Distribution Analysis

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Homework Help Overview

The discussion revolves around a physics problem involving timesteps and the application of normal distribution in analyzing a sequence of values. Participants are exploring the mathematical relationships and approximations related to exponential growth over multiple timesteps.

Discussion Character

  • Mathematical reasoning, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the derivation of an approximation related to exponential functions and timesteps, questioning the use of Taylor series and the definition of the exponential function.

Discussion Status

There is an ongoing exploration of the mathematical concepts involved, with some participants confirming the correctness of the approximation and others seeking further clarification on the underlying definitions and methods used.

Contextual Notes

Participants reference previous threads for additional context, indicating that there may be established methods or definitions relevant to the current discussion.

courtrigrad
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Hello all

Let [tex]\delta t[/tex] be a timestep. Then the mean is equaled to [tex]\mu\delta t[/tex] where [tex]\mu[/tex] is a constant. Assuming a nornal distribution, [tex]\frac{S_{i+1}-S_{i}}{S_i} = \mu\delta t[/tex]

[tex]S_{i+1} = S_i(1 + \mu\delta t)[/tex]. Hence after M timesteps we have:

[tex]S_m = S_0(1+\mu\delta t)^M = S_0e^{Mlog(1+\mu\delta t)} \doteq S_{M}=S_{0}e^{[\mu M(\delta t)]}= S_0e^{\mu T}[/tex] How do we get the last part (the approximation)?

Thanks :smile:
 
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The way i see it,the approximation should be
[tex]S_{M}=S_{0}e^{[\mu M(\delta t)]}[/tex]

It might help if you came up with more explanation.

Daniel.
 
yes that is correct. how do they get this? do they use taylor series?
 
No,the definition of "e"...Check one of the other threads where i showed you on a similar problem...

Daniel.
 

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