Calculating Satellite Orbital Radius from Period

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Homework Help Overview

The discussion revolves around calculating the orbital radius of a satellite using its orbital period. Participants are exploring the relationship between orbital period and radius, particularly in the context of gravitational forces and circular motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to derive the orbital radius using formulas related to gravitational force and centripetal acceleration. There are questions about the validity of the formulas used and the calculations performed. Some participants are also discussing the need for clarity on the values used in calculations.

Discussion Status

The discussion is ongoing, with participants providing various approaches and questioning each other's calculations. Some guidance has been offered regarding the need for proper bracket placement in calculations, and there is a recognition of potential errors in the numerical inputs. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants are working with a specific orbital period value of T = 5760 s, and there is a focus on ensuring that calculations are performed correctly to arrive at the expected result.

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I need to find the orbital radius of a satilite, while only knowing its orbital period.


i tried..

a = 4π²r/T²
Fnet = Fg
a = Gm/r²

Gm/r² = 4π²r/T²
r = cuberoot(T²Gm/4π²)

didnt work out..
 
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What??What are u saying by "didn't work out" ?Your formula is okay for a circular orbit...

Daniel.
 
Hmm..i keep getting 3.19x10^7

but the answer is 6.95x10^6
 
Try this:
From the period, find the speed (simple calculation). Then, use this formula to find the radius:

[tex]v=\sqrt{\frac{Gm_E}{r}}[/tex]
 
hmm, in order to find the speed don't you need the radius?

like v = 2πr/T ?
 
Format said:
Hmm..i keep getting 3.19x10^7

but the answer is 6.95x10^6

I see nothing wrong with your approach. Why don't you post the numbers given (actually just the value of T), so we can check the calculation ?
 
Oh yeah. Just give me a second to think about this...
 
i guess that would help lol..

A satilite has an orbital period of T = 5760 s. What is the average orbital radius of its orbit?
 
Last edited:
Format said:
Hmm..i keep getting 3.19x10^7

but the answer is 6.95x10^6

Please post the initial text of the problem...

Daniel.
 
  • #10
I get 6.95 * 10^6 m.

You must have made a calculation error. Show us your working, and we'll show you what's wrong.
 
  • #11
Format said:
I need to find the orbital radius of a satilite, while only knowing its orbital period.


i tried..

a = 4π²r/T²
Fnet = Fg
a = Gm/r²

Gm/r² = 4π²r/T²
r = cuberoot(T²Gm/4π²)

didnt work out..
I did exactly that and got 6.95 x 10^6 m. Maybe you punched in the numbers wrong...
 
  • #12
well isn't this anoying..
k i put the cube root of..

( (5760²)(6.67x10^(-11)(5.98x10^24) ) / 4π²
 
  • #13
wait...i see a missing bracket, one sec lol

damn didnt make a difference...wut am i doing wrong?
 
Last edited:
  • #14
Without using the calculator i could show that the result is
[tex]6\cdot 10^{6} <r<7\cdot 10^{6}[/tex]

:wink:

So how about pluggng in the numbers properly...

Daniel.
 
  • #15
Format said:
well isn't this anoying..
k i put the cube root of..

( (5760²)(6.67x10^(-11)(5.98x10^24) ) / 4π²
yeah, you're missing a bracket. :-p
 
  • #16
ive done this like 10 times now and added the brackets...still gettin 3.2x10^7 lol
 
  • #17
OK, show me exactly what you typed into you calculator.
 
  • #19
Okay:U need to take 3-rd order root from:
[tex]\frac{(5.76)^{2}\cdot 1000^{2}\cdot 6.67\cdot 10^{-11}\cdot 5.98\cdot 10^{-24}}{4\pi^{2}} \simeq 300\cdot 10^{18}[/tex]

Daniel.
 
  • #20
ok i got it to work haha, thanks for the help guys
 
  • #21
[tex]r = (t / (2pi)) ^ {2 / 3} * (G * M) ^ {1 / 3}[/tex]
r = 6942704.95871195 meters
 

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