Efficient Integration Techniques: Expert Help for (e^x - 2)^2 Equation

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The discussion focuses on solving the integral of the function 4/(e^x - 2)^2. The recommended approach involves expanding the denominator to 4/(e^2x - 4e^x + 4), substituting u = e^x, and applying partial fractions to simplify the expression. The final solution is derived as -4/(e^x - 2) + 4/(e^x - 2)^2. Participants emphasize the importance of verifying the solution by differentiating it to ensure it aligns with the original function.

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4/(e^x - 2)^2

That was a test question that I had tonight...solutions won't be up for a while, wondering how to approach it.

I thought of expanding the bottom bracket, then multiplying by (e^x)/(e^x), substituting u=e^x and then using partial fractions...not sure if it is right, thanks in advance.
 
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Yes,i would have done it the same way:multiply both the numerator & the denominator with the e^{x} and then make the obvious substitution e^{x}---->u and then use partial fractions.

Daniel.
 


Hello, thank you for reaching out for expert help with your integration question. Your approach of expanding the bottom bracket and using partial fractions is a good start. Let me walk you through the steps to solve this efficiently.

First, let's expand the bottom bracket to get 4/(e^x - 2)^2 = 4/(e^2x - 4e^x + 4). Then, we can substitute u = e^x to get 4/(u^2 - 4u + 4). Next, we can use partial fractions to split this into two separate fractions: 4/((u-2)^2) = A/(u-2) + B/(u-2)^2.

To solve for A and B, we can equate the numerators and simplify to get A(u-2) + B = 4. Plugging in u = 2, we get B = 4. Then, plugging in u = 0, we get A = -4. So our final equation becomes -4/(u-2) + 4/(u-2)^2.

Now, we can substitute back in e^x for u to get -4/(e^x - 2) + 4/(e^x - 2)^2. This is the final solution for our integral.

Remember to always check your work by taking the derivative of your solution to make sure it matches the original equation. I hope this helps and good luck on your test!
 

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