How Does Magnetic Force Affect an Ion Moving Along the Line x=y?

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Homework Help Overview

The discussion revolves around the effects of magnetic force on an ion moving along the line x=y in the x-y plane. The original poster presents a scenario where the ion experiences a magnetic force when moving in the positive x direction but none in the positive y direction, raising questions about the force's magnitude along the specified line.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest breaking down the ion's velocity into x and y components to analyze the magnetic force. There are discussions about the implications of the constant speed and how to apply the magnetic force equation, including considerations of angles and vector notation.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have offered guidance on using vector notation and breaking down components, while others are questioning the implications of the given conditions and the relationship between velocity and magnetic force.

Contextual Notes

There is an emphasis on the assumption that the ion's speed remains constant across different directions, which may influence the analysis of the magnetic force. The participants are also considering the direction of the magnetic field based on the forces experienced by the ion.

triplezero24
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Ok, an ion experiences a magnetic force of 6.2X10^-16 N when moving in the positive x direction, but no force when moving in the positive y direction. What is the magnitude of magnetic force exerted on the ion when it moves in the x-y plane along the line x=y? Assume the ions speed is the same in all cases.

I know that for this problem F=qvB sin theta. Because the ion travels on the line x=y, then the theta angle is 45. Other than that I have no clue. :confused:

Thanks again for any help. :smile:
 
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break it up into an x component and a y component velocity and find the force for each.
 
It says the speed is the same in all cases.
 
It says the speed is the same in all cases.
so what?
break it up into an x component and a y component velocity and find the force for each.
for sure v_x and v_y is not equal to v... but can you find v_x and v_y in term of v using the P******* theorem? (really have no idea how to spell that word)
 
triplezero24 said:
It says the speed is the same in all cases.

StatusX means use vector notion instead of F=qvB sin theta.

[tex] F= q \vec{v} \times \vec{B} =( v_y B_z - v_z B_y )\hat{x} + (v_z B_x - v_x B_z )\hat{y} + (v_x B_y - v_y B_x)\hat{z}[/tex]

Some terms will be zero though if [tex]\vec{B}[/tex] is perendicular to [tex]\vec{v}[/tex]
 
triplezero24 said:
Ok, an ion experiences a magnetic force of 6.2X10^-16 N when moving in the positive x direction, but no force when moving in the positive y direction.
This should tell you two things:
(1) The direction of the magnetic field (B)
(2) The value of qvB (apply [itex]F = qvB sin \theta[/itex], where [itex]\theta[/itex] is the angle between v and B)

What is the magnitude of magnetic force exerted on the ion when it moves in the x-y plane along the line x=y? Assume the ions speed is the same in all cases.
Once you've figured out (1) and (2), all you need to find your answer is to again apply [itex]F = qvB sin \theta[/itex] with this new angle. What angle does the ion velocity make with the B field when it travels the line x=y?
 

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