Math

[gillgill]

Can you guys help me solve this inequality

√(x+2) + 1/x+2 >0

thanks

[Justin Lazear]

Is that

\sqrt{x+2} + \frac{1}{x} + 2 > 0
or
\sqrt{x+2} + \frac{1}{x+2} > 0

?

You must be careful with your notation to ensure that there isn't ambiguity!

--J

[VietDao29]

Hi,
Try to arrange it to:
\frac{A}{B} <= 0
Or
\frac{A}{B} >= 0
Where A = a_{1} \times a_{2} \times a_{3} \times ... \times a_{n}
and B = b_{1} \times b_{2} \times b_{3} \times ... \times b_{k}
Then just simply solve the inequation by drawing a chart to see if each element is positive or negative or zero. And finally, see if \frac{A}{B} is positive or negative or zero in each case.
Hope this help,
Viet Dao,

[gillgill]

o..icic..thx...
do you have to do the "cases" for it?

[dextercioby]

You may wanna begin by stating clearly the domain of the "x"...And then look for those "x" which would satisfy your inequation.

Daniel.

[primarygun]

If the question is designed as "equal or bigger",it is more tricky.

[The Bob]

I still want to know what √(x+2) + 1/x+2 >0 is.

How we decided yet???

Is it:

\sqrt{\frac{(x + 2) + 1}{x + 2}} > 0

Is it:

\sqrt{(x + 2) + \frac{1}{x + 2}} > 0

or something else???

The Bob (2004 ©)