How can I simplify this fraction: (x+2)/(x-1) * (4x+1)/(x-1)?

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The discussion focuses on simplifying the fraction (x+2)/(x-1) * (4x+1)/(x-1). Participants confirm that the correct method involves inverting the denominator and multiplying, which leads to the expression (x+2)/(x-1) * (x-1)/(4x+1). The x-1 terms cancel out, simplifying the fraction to (x+2)/(4x+1). This method is a standard approach to dividing fractions, reinforcing foundational algebra concepts.

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[tex]\frac {x+2} {x-1} \frac \frac {4x+1} {x-1}[/tex]

Would using the bowtie method work? Cross multiply and then subtract the two answers found from each other, and put that result over the multiplaction of the two denominators. ?

EDIT: I messed up the Latex thing. THe 4x-1 and the x-1 are supposed to be a fraction under the x+2/x-1
 
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So you mean

[tex]\frac{\frac{x+2}{x-1}}\frac{4x+1}{x-1}}[/tex]
?

You learned how to divide fractions in the fourth grade: invert the denominator and multiply. This is:
[tex]\frac{x+2}{x-1}*\frac{x-1}{4x+1}[/tex]

Can you reduce that?
 
Agreed. Dividing is the same as multiplying by the reciprocal. So when you do this the [tex]x - 1[/tex]'s cancel out.
 

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