Graphing Trigonometric Functions Question

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Discussion Overview

The discussion revolves around the challenges of graphing the trigonometric functions cosecant (csc), secant (sec), and cotangent (cot), particularly in contrast to the more straightforward graphing of sine (sin), cosine (cos), and tangent (tan). Participants explore the properties of these functions, including their continuity and points of discontinuity.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant expresses difficulty in graphing csc, sec, and cot after successfully graphing sin, cos, and tan.
  • Another participant points out that csc(θ) is undefined when sin(θ) = 0, indicating points of discontinuity.
  • It is noted that sec(x) and csc(x) are not smooth graphs and are not continuous functions.
  • A participant highlights that tan(x) also has points where it "blows up," specifically where cos(x) = 0, indicating its discontinuity.
  • Further clarification is provided that tan(x) breaks at odd multiples of π/2 and cot(x) breaks at integer multiples of π.

Areas of Agreement / Disagreement

Participants generally agree on the discontinuous nature of csc, sec, tan, and cot functions, but the discussion remains unresolved regarding specific methods for graphing these functions.

Contextual Notes

Participants have not fully explored the implications of discontinuities on graphing techniques, and there may be missing assumptions regarding the understanding of function behavior at critical points.

DLxX
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Ok I can graph sin(x) , cos(x) , and tan(x) pretty easily, but I'm having a hard time graphing the csc, sec, and cot ones. For the first three I just found the values of pi/2 pi 3pi/2 and 2pi. So for example pi/2 for sin(x) would be sin 90 or sin pi/2 which is equal to 1. I then just put a dot at 1 and did the same thing for the rest of the angles in radian measure and then just draw a smooth curve through them, but how do I do this with csc, sec, and cot?
 
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Consider what happens to csc([itex]\Theta[/itex]) When Sin([itex]\Theta[/itex])=0 .
 
In other words, you can't draw "smooth" graphs for sec(x) and csc(x) (or for that matter tan(x) and cot(x)). They aren't "smooth"- they aren't even continuous.
 
You should have seen that when u graphed "tan".You said u graphed it,so u have noticed that is "blows up" in certain points (namely where the cosine is zero).It's discontinuous as well.


Daniel.
 
[tex]\tan{x}[/tex], 'breaks up' at [tex]\frac{\pi}{2}(2k-1)[/tex], and [tex]\cot{x}[/tex], 'breaks up' at [tex]k\pi[/tex].
 

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