Electrostatics: Calculating Charge on Suspended Spheres

  • Thread starter Thread starter Neerolyte
  • Start date Start date
  • Tags Tags
    Electrostatics
Click For Summary

Homework Help Overview

The discussion revolves around a problem in electrostatics involving two small spheres with equal charges suspended by silk fibers. The spheres are in static equilibrium, with a specified distance between them and a known mass.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the spheres, including tension and gravitational force. There is uncertainty about the relationship between the tension components and the repulsive force, as well as the relevance of the string length in the calculations.

Discussion Status

Some participants have identified the forces involved and are exploring the equilibrium conditions. Guidance has been offered regarding the symmetry of the problem and the relationship between the tension and repulsive forces, although there remains some uncertainty about the next steps in the analysis.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for solving the problem. The discussion includes questions about assumptions related to the forces and geometry involved.

Neerolyte
Messages
13
Reaction score
0
two small spheres, each with 0.120g, have equal charges placed on them. Each sphere is suspended from the same point by its own silk fibre which are 75.0cm long. The repulsive force between them keep their centres 10.0cm apart. What is the charge on each sphere?
 
Last edited:
Physics news on Phys.org
It's a static equilibrium problem. Start by identifying all the forces acting on each sphere.
 
hm...this is what i think of it

Since there is strings involved, there must be tension. And since there are 2 strings connected to 1 point holding the 2 spheres. There must be T1 and T2. T1 and T2 must have components. We knew the mass of the two spheres so we know what Fg is, which equals to T1y and T2y.

Here is thing i don't know. Is T1x the repulsive force? IF it is, why does the data contain the string's length...and IF it is NOT, then I'm not sure how to do it...

yes i did a FBD, and identified all the forces. Fg, T, and repulsive force, that's it..
 
Neerolyte said:
Since there is strings involved, there must be tension. And since there are 2 strings connected to 1 point holding the 2 spheres. There must be T1 and T2. T1 and T2 must have components. We knew the mass of the two spheres so we know what Fg is, which equals to T1y and T2y.
Right. But the symmetry of the problem tells you that T = T1 = T2; you only need to deal with one of the two masses. And yes, the tension in the string exerts a force on the mass with components Tx and Ty. For equilibrium, Ty = mg.


Here is thing i don't know. Is T1x the repulsive force? IF it is, why does the data contain the string's length...and IF it is NOT, then I'm not sure how to do it...
The only forces acting horizontally are Tx and the repulsive force (F), so F = Tx. The length of the string and the distance between the masses will allow you to calculate the x and y components of the tension force. (Hint: One will be Tcos(theta); the other will be Tsin(theta).)

Next step: Rewrite the two force equations and solve for the repulsive force F.
 
yep got it ^_^

thank you very much
 

Similar threads

Replies
23
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 50 ·
2
Replies
50
Views
8K
Replies
21
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
8
Views
9K
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
6K
Replies
14
Views
2K