Does Special Relativity Affect the Work Needed to Accelerate a Particle?

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SUMMARY

The work required to accelerate a particle with mass m from rest to speed v_1 is expressed as work = (1/sqrt(1-(v/c)^2) - 1) * mc^2. This formula incorporates the Lorentz factor, gamma (γ), defined as γ = 1/(sqrt(1-(v/c)^2)). However, the final answer should be presented in terms of γ - 1, which does not explicitly include the speed of light, c. This distinction is crucial for aligning with the expectations of physics problem-solving platforms like Mastering Physics.

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  • Understanding of special relativity concepts, particularly kinetic energy and the Lorentz factor.
  • Familiarity with the equation for relativistic kinetic energy.
  • Basic knowledge of algebraic manipulation and factorization.
  • Concept of work-energy principle in physics.
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  • Study the derivation and implications of the Lorentz factor in special relativity.
  • Learn about relativistic kinetic energy and its applications in particle physics.
  • Explore the work-energy theorem in the context of relativistic speeds.
  • Review problem-solving strategies for physics questions on platforms like Mastering Physics.
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matpo39
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ok i have a question from mastering physics i thought i was doing it right but it gives me an incorrect answer.

How much work must be done on a particle with a mass of m to accelerate it from rest to a speed of v_1? (Express the answer in terms of mc^2.)

I figured that this would just be the kenetic energy which is givin by

K= mc^2/(sqrt(1-(v/c)^2) - mc^2

so i factored out an mc^2 and was left with

work= (1/sqrt(1-(v/c)^2) -1)*mc^2

but mastering physics says that the answer does not depend on c.
i don't see how this is possible

thanks for the help
 
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Express the answer in terms of mc^2. the answer is [tex]\gamma -1[/tex]
 
yes, that is my problem, the definition of gamma is 1/(sqrt(1-9V/c)^c)
so gamma itself contains a c and i don't think mastering physics will except the variable expression gamma as part of the answer because it is no where to be found in the problem.
 

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