Calculating Speed on an Inclined Plane | Mechanical Energy #2

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving a box sliding down a frictionless inclined plane, focusing on the concepts of mechanical energy, specifically kinetic and potential energy. The original poster seeks assistance with understanding the relevant formulas and calculations related to the scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of mechanical energy, suggesting that the potential energy at the top of the ramp should equal the kinetic energy at the bottom. There are calculations presented for potential energy and questions about the correct application of formulas.

Discussion Status

Participants are actively engaging with the problem, offering guidance on the relationship between potential and kinetic energy. There is a focus on ensuring that calculations are performed correctly, particularly regarding units and the setup of equations.

Contextual Notes

There is an emphasis on the initial conditions of the problem, such as the box starting from rest and the absence of friction. The participants are also considering the implications of these conditions on the energy calculations.

billyghost
Messages
5
Reaction score
0
A 19 kg box starts at rest and slides down a frictionless ramp. The length of the ramp is 4.5 m and the height above the ground at the top is 1.3 m. How fast is the box moving at the bottom of the ramp?

Unsure of inclined planes...help with formulas, etc.?
 
Physics news on Phys.org
Think conservation of mechanical energy (KE + PE). (Measure the potential energy from the bottom of the ramp.)

Mechanical Energy (at top of ramp) = Mechanical Energy (at bottom of ramp)
 
19 x 1.3 x 9.8 ?
 
billyghost said:
19 x 1.3 x 9.8 ?
That looks like a calculation of the PE at the top of the ramp: PE = mgh. (The units will be Joules.) Which happens to be the total mechanical energy, since it starts from rest. Since energy is conserved, this also equals the KE at the bottom of the ramp. ([itex]{KE} = 1/2 m v^2[/itex])

So set the PE at the top (mgh) equal to the KE at the bottom ([itex]1/2 m v^2[/itex]) and solve for the speed.
 
Therefore,velocity should be the square root of 2 x 9.8 x 1.3
 
Right. But be sure to give your answer with the proper units.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
4K