What is the Angular Speed of a Pulsar?

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Homework Help Overview

The discussion revolves around calculating the average angular speed of a pulsar, which is a type of neutron star that emits radio waves. The problem specifies the time interval between pulses as 0.0336 seconds and involves determining angular speed in radians per second.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for angular speed and the relationship between time and revolutions. There is a question regarding the value "6369" mentioned by one participant, prompting clarification on its relevance.

Discussion Status

Some participants are exploring the calculation of angular speed using the time between pulses and the concept of revolutions. There is an ongoing clarification regarding the values used in the calculations, and multiple interpretations of the problem are being examined.

Contextual Notes

Participants are discussing the context of their physics courses, which may influence their understanding and approach to the problem. There is a mention of different institutions and course numbers, indicating varying levels of familiarity with the topic.

elemnt55
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A pulsar is a rapidly rotating neutron star that continuously emits a beam of radio waves in a searchlight manner. Each time the pulsar makes one revolution, the rotating beam sweeps across the earth, and the Earth receives a pulse of radio waves. For one particular pulsar, the time between two successive pulses is 0.0336 s. Determine the average angular speed (in rad/s) of this pulsar.

i got w= change in theta / change in time
6369/.0336
 
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elemnt55 said:
A pulsar is a rapidly rotating neutron star that continuously emits a beam of radio waves in a searchlight manner. Each time the pulsar makes one revolution, the rotating beam sweeps across the earth, and the Earth receives a pulse of radio waves. For one particular pulsar, the time between two successive pulses is 0.0336 s. Determine the average angular speed (in rad/s) of this pulsar.

i got w= change in theta / change in time
6369/.0336
The rotation between 2 pulses is 1 revolution = [itex]2\pi[/itex] and the time it takes to make one revolution is [itex]\Delta T=0.0336s[/itex]

[tex]\omega=\frac{\Delta \Theta}{\Delta T}=\frac{2\pi}{0.0336 s}[/tex]

Not sure where you got 6369 from, but the above should give you the right answer.
 
Last edited:

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