Will a precipitate form wiht this CaCl2 and NaOH mixture

[ChemRookie]

The solubility product calcium hydroxide, Ca(OH)2 is 7.9 * 10tothe-6 at 25degcel. Will a precipitate form when 100mL of 0.10mol/L of CaCl2 solution and 50.0mL of 0.070 mol/L of NaOH solution are combined?

 

[ChemRookie]

anybody have any idea?

 

[thepatientmental]

To determine if a precipitate will form, we need to compare the Qsp (reaction quotient) to the Ksp (solubility product). The Qsp can be calculated by multiplying the concentrations of the ions involved in the reaction. In this case, the reaction is CaCl2 + 2NaOH -> Ca(OH)2 + 2NaCl. Therefore, the Qsp = [Ca2+][OH-]^2.

Plugging in the given concentrations, we get Qsp = (0.10 mol/L)(0.070 mol/L)^2 = 4.9 * 10^-4.

Since the Qsp is less than the Ksp (7.9 * 10^-6), a precipitate will not form. This means that the solution is not saturated and all of the ions will remain in solution. Therefore, no solid calcium hydroxide will form.