Invariants in general relativity

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SUMMARY

Invariants in general relativity (GR) are quantities that remain unchanged under transformations, such as the quantity J where \(\frac{dJ}{dt}=0\). The discussion explores the construction of the Lie group associated with the metric \(g_{ab}\) and the momentum density \(\pi_{ab}\), questioning how to derive the Casimir invariant from this group. Additionally, it addresses the complexities of calculating momentum \(\pi_{ab}\) from the Lagrangian of special relativity, emphasizing the necessity of alternative variables in the Hamiltonian formalism for GR, particularly the metric \(g_{\mu\nu}\) and momentum density \(\pi_{\mu\nu}\).

PREREQUISITES
  • Understanding of general relativity and its mathematical framework
  • Familiarity with Lie groups and their properties
  • Knowledge of Hamiltonian mechanics in the context of GR
  • Proficiency in tensor calculus and Lagrangian mechanics
NEXT STEPS
  • Study the properties of Casimir invariants in Lie groups
  • Learn about the Hamiltonian formalism in general relativity
  • Explore the derivation of momentum densities from Lagrangians
  • Investigate the role of tensors in defining invariants in GR
USEFUL FOR

The discussion is beneficial for theoretical physicists, mathematicians specializing in differential geometry, and researchers focused on the foundations of general relativity and its mathematical structures.

eljose
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do invariants in general relativity exist? i mean quantity J so [tex]\frac{dJ}{dt}=0[/tex]...

another question let suppose we take the Lie gorup of [tex]g_ab,\pi_ab[/tex] being g_ab and Pi_ab the metric and momentum density could we obtain the Casimir invariant of this group?...

the last question given the lagrangian of special relativity [tex]{g^1/2}Rdx^4[/tex] how do you calculate the momentum [tex]\pi_ab[/tex] ?...
 
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Any tensor that is identically zero is invariant in GR.
 
What do you mean by this operator [tex]\frac{d}{dt}[/tex] in GR...?Who's "t"...?

For the second question,how would you build the Lie group...?How do you define the Lie product...?

As for the last,things are not that easy.Hamiltonian formalism for GR needs other variables,for example working with [itex]g_{\mu\nu}[/itex] and [itex]\pi_{\mu\nu}[/itex] is not easy and usually,there are different notations of the elements of the metric.

Anyway,the definition is still the same:

[tex]\pi_{\mu\nu}=:\frac{\partial \mathcal{L}}{\partial^{0}g^{\mu\nu}}[/tex]

Daniel.
 

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