Calculating Forces in a Rotational System with a Wrecking Ball and Boom

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SUMMARY

The discussion focuses on calculating forces in a rotational system involving a wrecking ball weighing 5400 N and a uniform boom weighing 3800 N. The support cable forms a 32° angle with the horizontal, while the boom makes a 48° angle with the horizontal. The user struggles with identifying the correct pivot point and the appropriate equations to determine the tension in the support cable (FT). The equation presented, L(5400) - Lsin(32)FT + 1/2Lsin(48)3800=0, is incorrect for solving FT, indicating a need for clarification on the pivot point and force calculations.

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smith5029
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A wrecking ball (weight = 5400 N) is supported by a boom, which may be assumed to be uniform and has a weight of 3800 N. As the drawing shows, a support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32°, and the angle between the boom and the horizontal is 48°.

i'm drawing a blank really, i don't know what to use as my pivot point.
i had L(5400) - Lsin(32)FT + 1/2Lsin(48)3800=0
then i solved for FT but it was wrong, can you help me, or show me where to go
 
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the question wants to know what the force of the cables question is, and the length isn't defined but you can cancel it out right?
 
You posted in college help already. Don't double post.
 

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