Converting Velocity to RPM: Solving for Tension in a String

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Homework Help Overview

The discussion revolves around converting angular measurements and velocities in the context of a conical pendulum problem. Participants explore the relationship between angles, angular velocity, and tension in a string, specifically focusing on the conversion of degrees to revolutions per minute (rpm).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for time to convert degrees to rpm, and some suggest using angular velocity formulas. There is a focus on the application of trigonometric functions to determine angles and the subsequent calculations for tension and velocity.

Discussion Status

The discussion is ongoing, with participants questioning each other's methods and reasoning. Some guidance has been offered regarding the use of Newton's second law and the importance of understanding the thought process behind applying mathematical functions.

Contextual Notes

There are indications of confusion regarding the application of trigonometric functions and the conversion of angular measurements. Participants are navigating through assumptions about the relationships between the variables involved in the problem.

mugzieee
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how would i convert 23 degrees to revolutions per minute
 
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It depends on how long it took you to traverse that 23 degrees, I believe...
 
Rev's per minute is HERTZ times 60 in SI...Arch degrees is unitless.

Daniel.
 
A conical pendulum is formed by attaching a 0.100kg ball to a 1.00m-long string, then allowing the mass to move in a horizontal circle of radius 40.0cm.
What is the ball's angular velocity, in rpm?
from using sin, i obtained 23.57 degress. I am not sure how i would convert that to rpm
 
mugzieee,

You appear in this thread and others to be just blindly applying random functions like sin to all the numbers given in your problems, perhaps hoping to accidentally stumble across the right answer.

This is not a good method of solving problems.

Instead of telling us that you used the sine function, why don't you tell us what led you to want to use the sine in the first place? What is your thought process? How are you attempting to solve this problem?

- Warren
 
You have an angle.However,the angular velocity is found by drawing forces and writing the second law.

Daniel.
 
ok. the first part of the problem asked me to find the tension in the string. to do that i used Newtons second law where Tcos(theta)=mg
to find theta, i looksed at the picture, and since the radius(opposite side of the angle) and the hypotenuse were given, i applied sin, which was sin(theta)=r/l, which ledt to arcsin(.4/1) and i got theta to equal approximately 23 degrees. now for the second part of the problem, so far i could only think of finding the vlocity by the equation v=(omega)*(r), but then I am not sure how i would be able to convert velocity into rpm.
 

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