Can alternating series be grouped as geometric series for convergence?

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Homework Help Overview

The discussion revolves around the convergence of an alternating series, specifically examining the series \(\sum(-1)^n(\frac{3}{2})^n\). Participants are exploring the implications of the terms involved and the conditions for convergence in the context of power series and differential equations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the alternating series test and question whether the alternating factor can be grouped with the series to treat it as a geometric series. There is also consideration of the implications of the terms not approaching zero.

Discussion Status

The discussion is ongoing, with some participants affirming the reasoning that if the summand does not approach zero, the series cannot converge. There is a recognition of the divergence of the series based on the established definitions of convergence.

Contextual Notes

There is a focus on the definitions and tests for convergence, particularly in the context of alternating series and the behavior of their terms as \(n\) approaches infinity. The original poster's confusion about grouping terms indicates a need for clarification on the properties of series.

kdinser
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I'm reviewing power series for use in differential equations and I'm having some trouble remembering how to deal with alternating series.

For instance, if I have:
[tex]\sum(-1)^n(\frac{3}{2})^n[/tex]

if [tex]a_n=(\frac{3}{2})^n[/tex]
This fails the alternate series test because the limit of [tex]a_n[/tex] as n goes to infinity doesn't equal 0.

Can I group the (-1)^n into the fraction and call it a geometric series? In that case, it would diverge, |r| would be greater then 1.
 
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kdinser said:
I'm reviewing power series for use in differential equations and I'm having some trouble remembering how to deal with alternating series.

For instance, if I have:
[tex]\sum(-1)^n(\frac{3}{2})^n[/tex]

if [tex]a_n=(\frac{3}{2})^n[/tex]
This fails the alternate series test because the limit of [tex]a_n[/tex] as n goes to infinity doesn't equal 0.

Can I group the (-1)^n into the fraction and call it a geometric series? In that case, it would diverge, |r| would be greater then 1.

Yes, both ways are fine.
 
thanks for the help.
 
If the summand doesn't go to zero, the series cannot converge, regardless of whether it is alternating or not (using the most common definition of convergence).
 
Data said:
If the summand doesn't go to zero, the series cannot converge, regardless of whether it is alternating or not (using the most common definition of convergence).

Yes, you're right. This is the best way to solve the problem. The summand doesn't go to zero so the series diverges.
 

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