How Does Refraction Affect Image Location in a Bi-Radial Mirror?

[Jacob87411]

A piece of glas has an index of refraction of 1.5. The ends are hemispheres with radii 2 cm and 4 cm, and the distance that separates the centers of the hemispherical ends. A point object is located in air 1 cm from the left end of the glass. Find the location of the image of the object due to refraction at the two spherical surfaces.

So on the left end the mirror has a radius of 2 cm, and on the right it is of 4 cm and the two are separated by 8 cm.

Im thinking of using the equation: n2-n1/R = n1/d0 + n2/di. If so I will have to use it twice, one for each radius, which would give me two different di, then average them. Thats my thinking at least, not sure if its correct

 

[GCT]

Tis a lens, not a mirror...mirror's don't refract.

Find the focal length using the maker's equation (or its derivative).

The rest should be simple.

 

[Jacob87411]

Ah..now i feel dumb

1/f = (n-1) (1/R1 - 1/R2)
n=1.5
R1=2
R2=4
Simple indeed, thanks