Deriving Coefficient of Static Friction for Inclined Textbook and Coin

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SUMMARY

The discussion centers on deriving the equation for the coefficient of static friction (μ) between a textbook inclined at an angle (θ) and a coin. The participants confirm that the equation μ = Ff/Fnormal is accurate, where Ff is the static friction force (FgxSINθ) and Fnormal is the normal force (FgxCOSθ). The final expression simplifies to μ = |-(mg) sinθ / (mg) cosθ|, confirming the correctness of the derivation. The consensus among participants validates the approach and calculations presented.

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ok, our class got an assignment where we have to derive an equation for coefficient of static friction between our textbook (inclined at an angle theta) and a coin. The vale of the angle and the mass of the coin are not given. I have come up with the following equation and need to know if it is correct.

u = Ff(static)/Fnormal
*using components of the force of gravity, i determined Ff to be FgxSINxTheta and Fnormal to be FgxCOSxtheta
so,
u = FgxSINxTheta/FgxCOSxtheta

does this seem correct?

thanks for looking.
 
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[tex]mg sin\theta[/tex] is the gravitational force down the ramp, so
[tex]-(mg) sin\theta[/tex] is the force of static friction.

[tex]mg cos\theta[/tex] is indeed the force normal

[tex]\mu=\frac{F_{friction}}{F_{normal}}[/tex]

[tex]\mu[/tex] must be positive, so
[tex]\mu=\mid \frac{-(mg) sin\theta}{(mg) cos\theta}\mid[/tex]

Which looks exactly like what you got except you call it Fg and I called it mg
 
thanks, i just asked a friend and he got the same thing, so this must me right :smile:
 

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