Understanding the Momentum Operator in Quantum Mechanics

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Homework Help Overview

The discussion revolves around the origins and understanding of the momentum operator in quantum mechanics, specifically its formulation and relation to wave functions and the De Broglie relation.

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  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the derivation of the momentum operator and its connection to the wave number and the operator K. Some participants explore the implications of the momentum operator as an eigenstate of a plane wave and discuss the necessary mathematical foundations for its formulation.

Discussion Status

Participants are actively engaging with the problem, offering insights and clarifications regarding the momentum operator. There is a mix of perspectives on the clarity of the original textbook explanation, and some participants suggest alternative resources for further study.

Contextual Notes

The original poster expresses uncertainty about their understanding and the adequacy of their textbook, while others provide varying opinions on the quality of the material and suggest additional texts for reference.

Dathascome
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Ahoy hoy...I'm having some trouble understanding exactly where the momentum operator comes from. The momentum operator is P=-ih/(2*pi)*d/dx
I know that according to the DeBroglie relation p=kh/(2*pi)
and in the first chapter of my book we introduce the operator K=-id/dx
which is hermitian (which is necessary for getting real eigenvalues). So they say in the book that the P opertor is just P=hK/(2*pi)...but I don't see why. Is there some sort of relation between the wave # k and the operator K?
When I asked my professor all he said was something about the units of K being right, but I don't even see that.
Any help would be greatly appreciated.
 
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I don't know the argument used in the book, but if you consider a plane wave (state with a well defined momentum):

[tex]\psi(x)=Ae^{ikx}[/tex], then this is an eigenstate of the momentum operator with eigenvalue [itex]p=\hbar k[/itex].
Does that clear it up a bit?
 
What book do you use...?I bet it's not a good one.A proof that in the coordinate representation the momentum operator (for a general axis 'i') [tex]\hat{P}_{i}[/tex] has the form

[tex]\hat{P}_{i}=-i\hbar\frac{\partial}{\partial x_{i}}[/tex] *

would use 3 things:
1.De Broglie's relation [itex]\vec{p}=\hbar\vec{k}[/itex]
2.Parseval identity;
3.Fourier transformation of the wavefunction.

Daniel.
------------------------------------------------------------
* valid in the Schrödinger picture in Dirac's formulation.
 
You can derive the momentum operator by calling the change in time of the position expectation value the "velocity":

[tex]<p> = m \frac{d}{dt} \int \Psi^*(x,t) \ x \ \Psi(x,t) \ dx[/tex]

This can be put into the form of an operator between the wavefunction and its conjugate. You'll need to first move the time derivative inside the integral, use the schroedinger equation to get [itex]d\Psi(x,t)/dt[/itex], and integrate by parts a couple times, getting rid of the boundary term since the wavefunction must go to 0 at infinity. You'll end up with:

[tex]<p> = \int \Psi^*(x,t) (-i \hbar )\frac{d\Psi(x,t)}{dx} \ \ dx[/tex]
 
Thanks everyone, I think that cleared things up for me. It's an undergrad class and the book I'm using is "principles of quantum mechanics" by R.Shankar. It's probably not the book, it's most likely me :cry:
Does anyone have any suggestions of a good book to compliment the one I have already?
 
I thought Shankar's book is pretty good.It's advanced,compared,let's say to an introductory text like Griffiths or Blokhintsev,but pretty good on the ensemble...

Cohen-Tannoudji is very calculative,though the structure of the material is not appealing with those "Compléments".If u like more Messiah's book,be my guest.

Daniel.
 

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