Wavelength of Radio Waves Emitted by a Resonant Circuit in a Radio Receiver

Click For Summary

Homework Help Overview

The discussion revolves around calculating the wavelength of radio waves emitted by a resonant circuit in a radio receiver, given the circuit's inductor and capacitor values. The subject area includes concepts from electromagnetism and wave properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the wavelength using the frequency derived from the circuit parameters but encounters issues with the method suggested. Some participants clarify the relationship between frequency and wavelength using the wave equation, while others discuss the implications of providing direct answers versus encouraging independent problem-solving.

Discussion Status

Participants are exploring the relationship between frequency and wavelength, with some providing equations and clarifications. There is a mix of guidance and commentary on the nature of assistance being offered, indicating a productive exchange of ideas without a clear consensus on the best approach.

Contextual Notes

There is an indication that the original poster may be struggling with the application of wave properties and the implications of using certain formulas. The discussion reflects a balance between providing necessary information and encouraging self-reliance in problem-solving.

waywardtigerlily
Messages
10
Reaction score
0
A resonant circuit in a radio receiver is tuned to a certian station when the inductor has a value of 0.151mH and the capacitor has a value of 21.2pF. Calculate the frequency of the radio station.

Frequency is 2.81 MHz ( I got this one right)

B) what is the wavelength of the radiowaves emited by the radio station?
I was told to do this just take 1/f,but this gave me a wrong answer. Is there another way of going about it?
 
Physics news on Phys.org
1\f is the period,

for wavelength you want to use the equation for all waves

[tex]v = f \lambda[/tex]

where v is the speed of propagation of the wave
 
For this problem, [tex]v = c[/tex]. All electromagnetic waves travel at the speed of light, so:

[tex]f = c/\lambda[/tex]
 
Well there goes the chance of the OP doing any of the work for himself.
 
A lot of people don't know that, its not a question of doing work, its just a fact he needs.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
11K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K