Integration by parts (i think)

[PhysicsMajor]

Greetings all,

here goes....

The integral of (xe^(x))/((x+1)^(2))

Thanks

[whozum]

\int{\frac{xe^x}{(x+1)^2}}{dx}

u = \frac{-1}{x+1}

du = \frac{1}{(x+1)^2}

v = xe^x

dv = e^x(x+1)

\int{v}{du} = uv - \int{u}{dv}

\int{\frac{xe^x}{(x+1)^2}}{dx} = \frac{-xe^x}{x+1} + \int{e^x}{dx}

Hope that helps you out. Not a very hard problem from there ;)