Minimum Speeds for 100g Particles on Energy/Distance Graph

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Homework Help Overview

The discussion revolves around determining the minimum speeds required for 100 g particles to travel between two points on an energy versus distance graph. Participants are exploring concepts related to energy conservation and the relationship between kinetic and potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants suggest using conservation of energy to find minimum kinetic energy and speed. There are questions about how to derive force from a non-linear graph and the implications of conservative versus non-conservative forces.

Discussion Status

Some participants have provided guidance on using energy conservation principles, while others are questioning the definitions and implications of conservative forces in the context of the problem. Multiple interpretations of the energy relationships are being explored.

Contextual Notes

There is a mention of needing to consider work done in relation to a "Force vs Distance" graph, and the potential impact of factors like friction on energy conservation is being discussed.

Honore
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With reference to the attached "energy versus distance graph" of two particles;

a. What minimum speed (m/s) does a 100 g particle need at point A to reach point B?

b. What minimum speed (m/s) does a 100 g particle need at point B to reach point A?

Thank you.
 

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  • energy versus distance graph.JPG
    energy versus distance graph.JPG
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Use conservation of energy. First find the minimum kinetic energy needed to go from A to B, then get the speed from that.
 
Galileo said:
Use conservation of energy. First find the minimum kinetic energy needed to go from A to B, then get the speed from that.

In order to find the minimum kinetic energy, I think I have to find the total work done referring to a "Force vs Distance" graph. But, how can "Force" be found from a graph which is not linear?
 
Work = [itex]\int F dx[/itex]

Is this gravitational potential? In that case, its conservative, and you can ignore anything but the starting and ending points. You lost 2 Joules of PE to get from A to B, so you gained 2 Joules of KE.

[tex]KE = 1/2 mv^2[/tex]

[tex]2 = 1/2 (100g) v^2[/tex]
 
In one dimension, any position dependent force is conservative (the potential (or total?) energy is already given as a function of the position).
 
Isnt "position dependent force" part of the definition of "conservative force"? Say there was a resistance factor such as friction, the energy wouldn't be conserved then.
 

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