Potential Energy of 6kg Box Sliding Down 17m Incline

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SUMMARY

The potential energy (U) of a 6 kg box sliding down a 17 m incline at an angle of 34 degrees is calculated using the formula U = mgy, where m is the mass, g is the acceleration due to gravity (9.81 m/s²), and y is the height (17 m). The angle does not directly affect the potential energy calculation, as it is only relevant for determining the box's motion along the incline. The original potential energy of the box is 1,020.54 joules, confirming that the angle is extraneous for this specific calculation.

PREREQUISITES
  • Understanding of gravitational potential energy formula (U = mgy)
  • Basic knowledge of physics concepts related to motion and energy
  • Familiarity with units of measurement in physics (kilograms, meters, joules)
  • Concept of frictionless surfaces in physics
NEXT STEPS
  • Explore the concept of kinetic energy and its relation to potential energy
  • Learn about inclined plane physics and the role of angles in motion
  • Study the conservation of energy principle in mechanical systems
  • Investigate real-world applications of potential energy calculations
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding energy concepts in motion scenarios.

the_d
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A 6 kg box slides down a long, frictionless
incline of angle 34 degrees. It starts from rest at time
t = 0 at the top of the incline at a height 17 m
above the ground.
The acceleration of gravity is 9.81 m/s^2 :
What is the original potential energy of
the box relative to the ground?

i just don't know what to do with the angle. the formula is U = mgy, but where does the angle come into play?
 
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I've seen many questions where unnecessary information is given. It's just another way questions can test your knowledge.
 
asrodan said:
I've seen many questions where unnecessary information is given. It's just another way questions can test your knowledge.


u were right
 

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