Calculating Combinations with Constraints

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Homework Help Overview

The problem involves calculating the number of distinguishable arrangements of 10 pink balls and 15 purple balls, with the constraint that no two pink balls can be adjacent. The original poster expresses uncertainty about the method to arrive at the known answer of 8008.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss whether arrangements of varying sizes are allowed or if a fixed size of 25 balls is required. There is mention of breaking the problem into cases based on arrangement size and considerations about the distribution of purple balls to separate the pink balls.

Discussion Status

Some participants are exploring different interpretations of the problem, particularly regarding the size of arrangements. Guidance has been offered regarding the distribution of balls and the implications of the constraints, but no consensus has been reached.

Contextual Notes

There is a mention of a model used in the Einstein solid to illustrate a similar combinatorial problem, indicating a potential connection to broader combinatorial principles.

EvilPony
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You have 10 pink balls and 15 purple balls. How many distinguishable arrangements are possible if two pink balls cannot be next to each other?

I know the answer is 8008 but I have no idea how to get this
 
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are arrangements of any size allowable? ie: 1 ball, 2ball, ... arrangements, or do they have to be a fixed size?
 
im pretty sure you have to use all 25 every time
 
I'm on the verge of a solution but the computer lab is closing so I'll have to wait till tomorrow to post :frown:, sorry. Hopefully someone else will help out till then.

They must mean arrangements of all possible sizes, since the total number of arrangements of size 25 is much much less than 8008. My method involves breaking the situation into cases based on how big the arrangement is. I will provide more tomorrow. Good luck

-MS
 
MathStudent is wrong your problem does not mean arrangements of all possible sizes.

The pink balls can not be touching each other so you need if you have 10 pink you need 9 purple.

Now you have 6 purple balls left to distribute and 11 places to put it.

This model is used in the Einstein solid to model the multiplicity of a solid with r atoms and N units of energy to distribute.
[tex] \Omega = \binom{N+r-1}{r-1}[/tex]
 

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