Help Integrating Tripple Integral for x+y+z=1

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SUMMARY

The discussion focuses on evaluating the triple integral \(\iiint z \,dv\) over a solid tetrahedron defined by the planes \(x=0\), \(y=0\), \(z=0\), and \(x+y+z=1\). The setup involves the integral \(\int_{0}^1 \int_{0}^{1-x} \int_{0}^{1-x-y} z \,dz\,dy\,dx\). The key step in the solution is to correctly evaluate the inner integral using the anti-derivative \(-\frac{1}{3}(1-x-y)^{3}\), which simplifies the integration process.

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Alem2000
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the question is "evaluate [tex]\iiint z \,dv[/tex], of a solid tetrahedron bounded by the four planes x=0,y=0,z=0, and x+y+z=1"
I can set up the problem correctly but i can't seem to integrate it right
[tex]\int_{0}^1 \int_{0}^{1-x} \int_{0}^{1-x-y} z dzdydx[/tex]
[tex](1/2) \int_{0}^1 \int_{0}^{1-x} (1-x-y)^2dydx[/tex]
can someone please show me the last few steps of this problem? :confused:
 
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Open the brackets and integrate each term with corresponding limits...

Daniel.
 
For the evaluation of the inner integral, use the y-anti-derivative :
[tex]-\frac{1}{3}(1-x-y)^{3}[/tex]
 

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