Solutions to x^2==22(mod103) in Z103

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Discussion Overview

The discussion revolves around finding the number of solutions to the equation x^2 ≡ 22 (mod 103) within the set of integers modulo 103. The conversation touches on concepts from number theory, particularly quadratic residues and the Legendre symbol.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant requests to find the number of solutions for the equation x^2 ≡ 22 (mod 103).
  • Another participant introduces the concept of quadratic reciprocity as potentially relevant to the problem.
  • A participant inquires about the Legendre symbol, which is used to determine whether a quadratic equation has solutions modulo a prime.
  • A further explanation is provided regarding the Legendre symbol and its application to the specific case of x^2 ≡ 22 (mod 103), including the Law of Quadratic Reciprocity.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the number of solutions, as the discussion is still in the exploratory phase with various concepts being introduced.

Contextual Notes

The discussion involves assumptions about the properties of quadratic residues and the application of the Legendre symbol, which may depend on the definitions used by participants. There are also unresolved mathematical steps regarding the evaluation of the Legendre symbol for the specific case.

clueles
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find the number of solutions in z103

x^2==22(mod103)
 
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Have you seen quadratic reciprocity?
 
no i haven't
 
Legendre symbol?
 
The Legendre symbol [tex]\left(\frac{a}{p}\right)[/tex] is defined as 1 if [tex]x^2\equiv a\pmod p[/tex] has solutions, and -1 otherwise. (It's undefined or 0 if [tex]p\mid a[/tex].)

Thus for [tex]x^2\equiv22\pmod{103}[/tex] you're trying to decide the value of the Legendre symbol [tex]\left(\frac{22}{103}\right)[/tex].

Here's the 3-part Law of Quadratic Reciprocity:

[tex]\left(\frac{-1}{p}\right)=(-1)^{\frac{p-1}{2}}[/tex]

[tex]\left(\frac{2}{p}\right)=(-1)^{\frac{p^2-1}{8}}[/tex]

[tex]\left(\frac{a}{p}\right)=(-1)^{\frac{(p-1)(a-1)}{4}}\left(\frac{p}{a}\right)[/tex]

(If you're using a definition that doesn't include 0, you can move the two Legendre symbols to the same side for aesthetics.)
 

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