What is the Force and Tension in a Helicopter Truck Rescue?

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Homework Help Overview

The discussion revolves around a physics problem involving a helicopter lifting a truck, focusing on calculating the force exerted by the air on the helicopter blades and the tension in the cable connecting the truck to the helicopter. The context includes specific masses and an upward acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law, questioning the correct interpretation of acceleration and gravitational force. There is debate over whether to consider the upward acceleration as positive or negative in relation to gravity.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved and clarifying the signs of acceleration and gravitational force. Some guidance has been offered regarding the definitions of positive and negative directions.

Contextual Notes

Participants are navigating assumptions about the direction of forces and the overall acceleration, indicating potential confusion about the setup of the problem.

jungleismassiv
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After an incident over the mid-semester break involving a packet of Maltesers, a flooded creek,
and a wombat, a 15,000 kg salvage helicopter is lifting a 4,500 kg truck with an upward
acceleration of 1.4 m.s-2. Calculate:
1) The force the air exerts on the helicopter blades.
2) The tension in the cable between the truck and the helicopter

1. F = ma, so we know the mass is (15000 + 4500)

and would the acceleration be (9.8 + 1.4)?

2. Would T = m1*g + m1a?
 
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The accelerations are in opposite directions. If you define the direction up as positive then g = -9.8 m/s^2.
 
Corneo said:
The accelerations are in opposite directions. If you define the direction up as positive then g = -9.8 m/s^2.
Yes, but will the 1.4 be negative as well because the overall acceleration should be greater than 9.8?
 
No, the acceleration is what it is: 1.4m/s^2. You can take the upward direction as positive, so any downward pointing force is negative, and any upward pointing force is positive.
 

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