Pendulum Point of Suspension & Acceleration: Time Period Explanation

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SUMMARY

The discussion centers on the effect of upward acceleration on the time period of a simple pendulum. When the point of suspension accelerates upwards with acceleration 'a', the time period increases according to the formula T = 2π√(L/(g + a)), where 'g' is the acceleration due to gravity. This conclusion aligns with general relativity principles, which state that the effects of acceleration can mimic those of a gravitational field. The analysis also emphasizes the importance of using an inertial frame of reference to apply Newton's laws correctly.

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nishant
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if a pendulum's point of suspension is moving upwards with acceleration {a},then the time period of the simple pendulum will increase or decrease?{many people are using pseudo force to calculate this question,but that is to be used only when we are also moving with the point of suspension,but no where in the actual question is it written theat way?"
 
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The point of view is not important here. The fact that the pendulum is accelerating is key. General relativity says that we can not tell the difference between the effects of being in a gravitational field and the effects of actual acceleration. If the pendulum accelerates upward, then the pendulum will behave exactly as it would in a gravitational field of "g+a."

Of course this will be ignoring the effects of air resistance.
 
OK, if you want to prove it the hard way you can apply Newton's laws with the observer in an inertial frame of reference. Vertically, Ty - mg = ma. Use this to determine Tx in terms of displacement and you'll arrive at the same result

[tex]T = 2\pi \sqrt{\frac{L}{g + a}}[/tex]

On the other hand virtual gravity (grav. acceleration = g+a) is a convenient abstraction that you could use.
 

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