Calculating Cost of Charging a Battery

  • Thread starter Thread starter danne89
  • Start date Start date
  • Tags Tags
    Battery Charging
Click For Summary
SUMMARY

The discussion focuses on calculating the cost of charging a battery using a voltage function of v=11+0.5t V and a constant current of 2 A. The total power calculated over 5 hours is 122.5 W, resulting in an energy consumption of 0.6125 kWh. Given the price of 10 cents per kWh, the total cost for charging the battery for 5 hours is approximately 6.125 cents. Participants confirmed the calculations and emphasized the importance of unit consistency throughout the process.

PREREQUISITES
  • Understanding of basic electrical concepts, including voltage, current, and power.
  • Familiarity with integration techniques in calculus.
  • Knowledge of energy units, specifically kilowatt-hours (kWh) and watts (W).
  • Ability to perform unit conversions and calculations involving energy costs.
NEXT STEPS
  • Learn about the relationship between voltage, current, and power using Ohm's Law.
  • Study integration techniques for calculating work done in electrical systems.
  • Research energy pricing models and how to calculate costs based on consumption.
  • Explore battery charging efficiency and factors affecting charging time and cost.
USEFUL FOR

Electrical engineers, students studying physics or electrical engineering, and anyone involved in battery technology or energy management will benefit from this discussion.

danne89
Messages
180
Reaction score
0
A battery is being charged by a voltage v=11+0.5t V and a constant current of 2 A. The price of a kWh is 10 cent. How much is 5 hours battery-charging?

My work:
p = 22 + t
[tex]w= \int_{0}^{5} x dt = 25/5 + 22*5 = 122.5 W[/tex]
122.5 W in 5 h = 5 * 122.5 Wh = 0.6125 kWh
 
Engineering news on Phys.org
[tex]w= \int_{0}^{5} p(t) dt[/tex]

where p = VA = 22 + 1t correct?

Just integrate that from zero to five to get the power then do the last step... i think its correct.

you should end up getting 122.5 JOULES like you did... your answer is correct.

Just make sure your units are right.
 
Last edited:
I solved it. I did indeed just need to crack the units.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 4 ·
Replies
4
Views
4K