Why Does Reflected Light Experience a Phase Change?

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Discussion Overview

The discussion revolves around the phenomenon of phase change in reflected light, specifically addressing why a 180-degree phase change occurs when light reflects off a medium with a higher index of refraction, while no phase change occurs when reflecting off a medium with a lower index. The scope includes theoretical explanations and calculations related to optics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that reflected light experiences a phase change based on the refractive indices of the media involved, with specific equations provided to illustrate this.
  • One participant requests a deeper explanation of the phase change phenomenon rather than references to textbooks, expressing frustration with the lack of direct answers.
  • Another participant cites the Fresnel Relations to explain the phase change mathematically, indicating that the reflected electric field can be derived from boundary conditions at the interface of two dielectrics.
  • There is a challenge to provide a clear, specific explanation of why the phase change occurs, with one participant emphasizing the need for a more intuitive understanding rather than relying on external texts.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the explanation for the phase change, with some providing mathematical insights while others seek a more conceptual understanding. The discussion remains unresolved regarding the clarity of the explanation.

Contextual Notes

Limitations include the reliance on mathematical formulations without a consensus on their intuitive understanding. Some participants express dissatisfaction with references to textbooks, indicating a desire for more accessible explanations.

marlon
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Reflected light will experience a 180 degree phase change when it reflects from a medium of higher index of refraction and no phase change when it reflects from a medium of smaller index. This is very well known. However i am wondering why that is ? Can anyone give me some calculations that actually prove this ?

Thanks

marlon
 
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The "Fresnel Relations" in physics-optics give the reflected E' field as
E'=E_{incident}[(n_1-n_2)/(n_1+n_2)] for normal incidence.
This shows the phase change. The FRs are derived in most junior level EM or optics texts. They follow from the BCs on E and H at the interface of two dielectrics.
The transverse components of each are continuous.
 
The theory of reflection of light is presented in any textbook of optics.I liked and recommend the bible:M.Born & P.Wolf:"Principles of Optics",any edition,chapter 1,starting with page 36.


Daniel.
 
Guys, if it is so easy why not give me a specific explanation as to why the phase change happens in this particular case ? Dexter, referring to books is useless because i am never going to read that book. I am asking for an explanation and if you cannot give it then don't post just for the sake of posting...Please...

So my question still stands...Anyone who knows the answer ?


regards
marlon
 
Marlon,the equation Meir posted states that,for normal incidence,

[tex]E_{reflected}=E_{incident}\frac{n_{1}-n_{2}}{n_{1}+n_{2}}[/tex]

If [itex]n_{1} < n_{2}[/itex],then [itex]E_{reflected}= - k E_{incident}[/itex] (1)

,where [itex]k=:\frac{n_{2}-n_{1}}{n_{1}+n_{2}}>0[/itex] (2)

Okay.Now,u write,following (1) & (2)

[tex]E_{reflected}=k E_{incident}e^{i\pi}[/tex] (3)

Is it any clear?Guess not.I introduce the phases and the polarization vectors,okay,then

[tex]\vec{E}_{reflected}=\vec{e_{p}}E_{reflected}e^{i\left(\vec{k}_{reflected}\cdot\vec{r}-\omega t\right)}[/tex] (4)

Using (3),u see where that phase change comes from.

http://scienceworld.wolfram.com/physics/FresnelEquations.html

(For the graph).

Here's a nice course

http://www.ece.rutgers.edu/~orfanidi/ewa/

BTW,it's PHASE.



Daniel.
 
thanks dexter
 

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