How Long to Overtake Another Car at Different Speeds?

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SUMMARY

The discussion focuses on calculating the time it takes for a car traveling at 60.0 km/hr to overtake another car moving at 40.0 km/hr, with an initial distance of 100 meters between them. The relative speed of the overtaking car is determined to be 20 km/hr. By applying the formula for time, which is distance divided by velocity, the time taken to overtake is calculated to be 18.0 seconds. Key to this calculation is the conversion of units from kilometers to meters and hours to seconds.

PREREQUISITES
  • Understanding of relative velocity concepts
  • Basic knowledge of distance, speed, and time relationships
  • Ability to perform unit conversions (km to m, hr to sec)
  • Familiarity with basic algebraic equations
NEXT STEPS
  • Study relative velocity calculations in physics
  • Practice unit conversion techniques for speed and distance
  • Explore real-world applications of speed and time in automotive contexts
  • Learn about the implications of speed limits and safe overtaking distances
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding vehicle dynamics and safe driving practices.

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How long does it take an automobile traveling in the left lane at 60.0 km/hr to pull along side a car traveling in the right lane at 40.0 km/hr if the cars' front bumpers are initially 100 m apart?

I know the velocity of the car in the left is 60 and the velocity of the car on the right is 40. I also know it's imperative to find the velocity of the left car in relation to the right car in order to compare their distances. I found this to be 20 km/hr. What I don't know, however, is how to find out how far the car on the right goes before the car on the left reaches it. I know time is distance divided by velocity, so I figure that if I can find this distance and divide it by 20 km/hr, I'll have the time.

I also know the answer in the back of the book .. 18.0 seconds. The question is, how do I get it?
 
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catchup time in hrs = 100 m/(20 km/hr) = .1 km/(20 km/hr) = ?

catchup time in secs = ?
 
What I don't know, however, is how to find out how far the car on the right goes before the car on the left reaches it.
You don't need to know that. The whole point of finding the speed of one car relative to another is to be able to use the distance between them as the distance- and you are given that. You just have to be careful to convert from km to m and from hr to sec.
 

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