Help on Question: A Lightly Damped System Vibrates

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A lightly damped system with a period of 15.0 seconds experiences a significant amplitude decrease from 50 cm to 5.00 mm over 30 seconds. The discussion highlights the importance of the natural frequency, denoted as ω₀, which represents the frequency of the system without damping. To determine the new period if the damping force is removed, one must analyze the relationship between the damping term and the amplitude decay, utilizing the equation A = A(max) * e^(-wt) * cos(wt + ...). This equation is critical for understanding the system's behavior under varying damping conditions.

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  • Study the derivation and application of the equation A = A(max) * e^(-wt) * cos(wt + ...)
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Ady_h
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Help on question, pleasezzzzzz

Hi, iv been struggling with this question for some time now, so i thought if some1 can help on the follwoing quiestion:

Q) A lightly damped system vibrates with a period of 15.0s. In half a minute its amplitude decreases from 50cm to 5.00mm. What would be the period if the damping force were removed?

Thank you if u answer this question. :::ADY::: :smile: :smile: :smile:
 
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It takes a bit of work to find their definition of [itex]\omega_0[/itex] here, but this explains the frequency dependence on the damping term of an oscillator. [itex]\omega_0[/itex] is the frequency when no damping is present.

http://hyperphysics.phy-astr.gsu.edu/hbase/oscda.html
 
There is a fuction describing this.
As far as I can remember,it is A=A(max)*e^(-wt)*cos(wt+...)
Since you know that "In half a minute its amplitude decreases from 50cm to 5.00mm." you can find how much is that "w".But I am not very sure,may I can tell you the accurate one if you contact me at wangkehandsome@hotmail.com later.
 

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