What is the Minimum Time for a Subway Train to Travel Between Two Stations?

  • Context: Graduate 
  • Thread starter Thread starter x911gt2
  • Start date Start date
  • Tags Tags
    Physics Train
Click For Summary

Discussion Overview

The discussion revolves around determining the minimum time required for a subway train to travel between two stations, considering various parameters such as distance, maximum speed, acceleration, and jerk. The focus is on the mathematical modeling of the train's motion under these constraints.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant outlines the parameters of the problem, including distance, maximum speed, maximum acceleration, and maximum jerk, and provides an example input with a claimed correct answer.
  • Another participant suggests that the minimum time occurs when the train accelerates at the maximum jerk to its maximum speed, maintains that speed, and then decelerates at the maximum jerk to stop at the next station.
  • A similar point is raised by another participant, emphasizing the need to reduce acceleration to zero at the right moment to achieve maximum speed just before deceleration begins.
  • One participant clarifies the definitions of positive and negative acceleration, stating that negative acceleration refers to deceleration in the direction of motion, not backward movement.
  • Another participant questions the feasibility of the maximum acceleration value provided, suggesting that it may be too high for a train and proposing a lower maximum acceleration value based on typical train specifications.
  • A participant requests to see the calculations made by the original poster to better assist in identifying any missing elements in their approach.

Areas of Agreement / Disagreement

Participants express differing views on the maximum acceleration values and the implications of positive and negative acceleration. There is no consensus on the correct approach to the problem or the parameters involved.

Contextual Notes

Participants have not reached a consensus on the maximum acceleration values, and there are unresolved assumptions regarding the definitions of acceleration and jerk in the context of train motion.

x911gt2
Messages
1
Reaction score
0
I am working on a computer program that determines the minimum time it
will take for a subway train to go from one station to the next based
on a few parameters:

The parameters to the problem are all positive integers not greater than 1000.

* d - the distance between stations, in metres
* m - the maximum allowable speed of the train, in metres/sec
* a - the maximum absolute acceleration of the train, in metres/sec2
* j - the maximum absolute jerk, in metres/sec3

The train must be completely stopped at each station and must move in
one direction at speeds not exceeding m. Acceleration can be positive
(forward) or negative (backwards) but its absolute value must not
exceed a. The last parameter, jerk, is the rate of change of
acceleration in either direction. That is, acceleration cannot
increase or decrease at greater than this rate. This parameter
prevents toppling the standing passengers.

For example, if the inputs are:

d = 1000
m = 70
a = 20
j = 1

The correct answer to 3 sig figs is 31.7


I have gotten close to this, but I am missing something. Basically, I
am looking for the math to figure out the problem.

Thanks in advance.
 
Physics news on Phys.org
The minimum time will occur in the following situation:

The train accelerates from rest at the maximum jerk rate, up to its maximum allowed acceleration, which it then maintains until it gets to maximum allowed speed. This process is reversed at the other end of the trip, as the train comes to a stop. In between the accelerations, the train should travel at its maximum speed.

It is possible, of course, that there won't be time to reach maximum speed, in which case there will be no constant speed section of the trip.
 
James R said:
The minimum time will occur in the following situation:

The train accelerates from rest at the maximum jerk rate, up to its maximum allowed acceleration, which it then maintains until it gets to maximum allowed speed.

And as the train approaches its maximum allowed speed, it has to reduce its acceleration to zero at the maximum jerk rate. It has to start doing this at just the right time so that when the acceleration reaches zero, its velocity is at maximum.
 
x911gt2 said:
Acceleration can be positive
(forward) or negative (backwards) but its absolute value must not
exceed a.

I don't mean to be picky, but keep in mind that a positive or negative acceleration does NOT have to mean forward or backwards, respectively. A positive acceleration means it is accelerating in the direction of motion, while a negative acceleration can mean it is decelerating along the direction of motion. Since your problem stated that:

The train must be completely stopped at each station and must move in
one direction

It means it cannot go backwards. Thus, for this case, a negative acceleration can only mean a deceleration.

Zz.
 
Hm, are you sure the maximum acceleration is 20 m/s^2? That's about two "g" which is very very large for a train. I seem to remember reading somwhere that a typical maximum acceleration for a train is 0.1 "g", that is, 1 m/s^2. Perhaps your problem really specifies a maximum acceleration of 2.0 m/s^2?

I wouldn't want to stand up on a train accelerating at 2 "g"! A mass on a string would be hanging at an angle of about 63 degrees from the vertical. :eek:
 
Last edited:
x911gt2 said:
The correct answer to 3 sig figs is 31.7[/I]

I have gotten close to this, but I am missing something.

If you show us what you've done, someone can probably zero in on what you're missing. Otherwise all we can do is guess.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
8K
Replies
1
Views
2K
Replies
1
Views
7K
  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
8K
Replies
4
Views
4K