How Does an Electron Move in a Magnetic Field?

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SUMMARY

An electron moving in a magnetic field of 0.54T with a velocity perpendicular to the field traverses a circular path at a frequency of approximately 11.9 GHz. This frequency is calculated using the formula f = qB/2πm, where q is the charge of the electron (-1.6 x 10^-19 Coulombs), B is the magnetic field strength (0.54T), and m is the mass of the electron (9.11 x 10^-31 kg). The calculation confirms that the electron's motion is governed by the principles of electromagnetism.

PREREQUISITES
  • Understanding of electromagnetism principles
  • Familiarity with the charge and mass of an electron
  • Knowledge of the formula for frequency of charged particles in magnetic fields
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the Lorentz force and its effects on charged particles
  • Learn about cyclotron motion and its applications in physics
  • Explore advanced topics in electromagnetism, such as magnetic confinement
  • Investigate practical applications of electron motion in magnetic fields, such as in particle accelerators
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Students of physics, educators teaching electromagnetism, and anyone interested in the behavior of charged particles in magnetic fields.

DramaFoYoMama
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I can't seem to figure this one out as my Physics book is outdated. An electron enters a magnetic field of .54T w/ vel. perp. to the direction of the field. At what frequency does the electron traverse a circular path? A little guidance in the right direction would be appreciated.
 
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Nevermind. I just figured it out. :)
 


To answer this question, we can use the equation for the frequency of a charged particle moving in a magnetic field:

f = qB/2πm

Where f is the frequency, q is the charge of the particle (in this case, the charge of an electron is -1.6 x 10^-19 Coulombs), B is the magnetic field strength (0.54T), and m is the mass of the particle (in this case, the mass of an electron is 9.11 x 10^-31 kg).

Plugging in these values, we get:

f = (-1.6 x 10^-19 C)(0.54T)/2π(9.11 x 10^-31 kg)

= 1.19 x 10^10 Hz

Therefore, the electron will traverse a circular path at a frequency of approximately 11.9 GHz (gigahertz).

I would recommend checking with your teacher or a more updated physics book for confirmation and further explanation. Additionally, you can also try looking up examples or practice problems online to further understand this concept.
 

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