PDA

View Full Version : net magnetic field


EvaBugs
May4-05, 12:12 PM
I have a small question about net magnetic field.

If I have 3 straight conductors that are parallel where
-the current is to the left in conductor #3 (and situated at a distance b from #2)
-the current is to the right in conductor #2. (and is situated at a distance a from #1)
I have to find the net magnetic field exerted by #2 and #3 on the first conductor.


Using RHR I found that:
-conductor #3 , the magnetic field is directed out of the page;
-Conductor #2, the magnetic field is into the page.


To find the net magnetic field, should I use B= KI2/(b+a) - KI2/a

Thank you in advance

OlderDan
May4-05, 01:00 PM
Are the conductors arranged in the order of number? #2 between #1 and #3? And was it supposed to say

-the current is to the left in conductor #3 (and situated at a distance b from #1)

and

I have to find the net magnetic force exerted by #2 and #3 on the first conductor

EvaBugs
May4-05, 01:01 PM
Yes, it's supposed to say that. They are placed on top of the other.

OlderDan
May4-05, 01:07 PM
If I am reading it right, the denominator a+b should be b itself. Are you looking for just the magnetic field, or the force on wire #1?

EvaBugs
May4-05, 01:10 PM
For the net B on wire #1

-the current is to the left in conductor #3 (and situated at a distance b from #2)
-the current is to the right in conductor #2. (and is situated at a distance a from #1)

OlderDan
May4-05, 01:12 PM
For the net B on wire #1

-the current is to the left in conductor #3 (and situated at a distance b from #2)
-the current is to the right in conductor #2. (and is situated at a distance a from #1)

Then the b+a should be correct

If #1 is on top, then your field directions are reversed. If #1 is on the bottom you have them right

EvaBugs
May4-05, 01:14 PM
Yes, it is at the bottom

Thank you