gillgill
May5-05, 12:20 AM
Poker hands...
1. How many ways are there to obtain these three highly-rated combinations below?
a. Four of a kind. -Four cards of the same rank and one other card
b. Full House. -Three cards of the same rank and two cards both of another rank. ( A triple, or three of a kind, and a pair.)
c. Two pairs. -Two pairs of cards of two distinct ranks and a fifth card of another rank.
2. Suppose you play a game in which only three cards are deal: How many ways are there to obtain one pair?
3. Suppose four cards are dealt. How many ways are there to obtain one pair?
am i doing these correctly?
1a. 13C1 X 48C1 = 624
b.13C1 X 4C3 X 12C1 X 4C2 = 3744
c.13C2 X 4C2 4C2 44C1 = 123,552
2.13C1 X 4C2 X 12C1 X 4C1 = 3744
3. 13C1 X 4C2 X 12C1 X 4C1 X 11C1 X 4C1 = 164736
am i right?
1. How many ways are there to obtain these three highly-rated combinations below?
a. Four of a kind. -Four cards of the same rank and one other card
b. Full House. -Three cards of the same rank and two cards both of another rank. ( A triple, or three of a kind, and a pair.)
c. Two pairs. -Two pairs of cards of two distinct ranks and a fifth card of another rank.
2. Suppose you play a game in which only three cards are deal: How many ways are there to obtain one pair?
3. Suppose four cards are dealt. How many ways are there to obtain one pair?
am i doing these correctly?
1a. 13C1 X 48C1 = 624
b.13C1 X 4C3 X 12C1 X 4C2 = 3744
c.13C2 X 4C2 4C2 44C1 = 123,552
2.13C1 X 4C2 X 12C1 X 4C1 = 3744
3. 13C1 X 4C2 X 12C1 X 4C1 X 11C1 X 4C1 = 164736
am i right?