Rationalize the denominators problem

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Homework Help Overview

The problem involves simplifying an expression that consists of two fractions, specifically focusing on rationalizing the denominators of each fraction and combining them. The subject area relates to algebraic manipulation and rational expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to rationalize the denominators and suggest finding a common denominator to combine the fractions. There is also a mention of factoring out common terms.

Discussion Status

Some participants have offered guidance on rationalizing the denominators and combining the fractions, while others seek clarification on the notation used in the expressions. Multiple interpretations of the problem setup are being explored.

Contextual Notes

There is a note of uncertainty regarding the proper formatting of the mathematical expressions, which may affect the clarity of the discussion.

Gughanath
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Could some one please express:

[2 (square root of 2)/[(square root of 3)-1] - [2(square root of 3)]/[(square root of 2)+1] in a simpler form. I am sorry if the expression looks completed, i didnt know how to write them properly on the forum, its bascailly a fraction (LHS) - another fraction (RHS). Please help :confused:
 
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Gughanath said:
Could some one please express:

[2 (square root of 2)/[(square root of 3)-1] - [2(square root of 3)]/[(square root of 2)+1] in a simpler form. I am sorry if the expression looks completed, i didnt know how to write them properly on the forum, its bascailly a fraction (LHS) - another fraction (RHS). Please help :confused:

The usual thing is to rationalize the denominators, then find common denominators, then combine terms. To rationalize, you have to multiply numerator and denominator of each fraction by the conjugate of the denominator.
 
[tex]\frac{2\sqrt{2}}{\sqrt{3} -1} - \frac{2\sqrt{3}}{\sqrt{2}+1}[/tex]

I would factor out a 2 and find a lowest common denominator, then go from there.
 
errmm...just before I continue...could you explain how you wrote that expression?
 
Click it, and on the bottom you should see Latex code reference.
 

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