How Do You Solve 10log1019 in Logarithms?

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Discussion Overview

The discussion revolves around evaluating the expression 10log1019, focusing on the properties of logarithms and how to handle coefficients in front of logarithmic functions. The scope includes mathematical reasoning and clarification of logarithmic properties.

Discussion Character

  • Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about how to evaluate 10log1019, particularly regarding the role of the coefficient in front of the logarithm.
  • Another participant mentions a property of logarithms that allows the coefficient to be absorbed into the argument of the logarithm, suggesting that this property is relevant to the discussion.
  • A different participant clarifies that the coefficient simply multiplies the result of the logarithm and argues that using the property to absorb the coefficient is unnecessary in this case.
  • One participant acknowledges the possibility of using the logarithmic property but emphasizes that the results would be the same regardless of the approach taken.
  • Another participant notes that logarithms can be computed using calculators, suggesting that changing the base is not necessary for this evaluation.

Areas of Agreement / Disagreement

Participants present differing views on whether to apply the logarithmic property that absorbs the coefficient into the argument. While some suggest it is a valid approach, others argue it is not necessary, indicating a lack of consensus on the best method to evaluate the expression.

Contextual Notes

The discussion does not resolve the uncertainty regarding the application of logarithmic properties, and there are no explicit assumptions stated about the context or conditions under which the properties apply.

m0286
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Hello sorry to post another so soon. This book is VERY hard to learn from... its not very good at explaining. The question says:
Evaluate the following logarithm: 10log1019. It never showed me how to do it when there's a number in front of the log. What I got from the log 1019 is log19/log10=1.27875. Now do I multiply this by 10 since that's the number infront.. I have no clue!
THNX AGAIN!
 
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Yes, there's also a property of logarithms that applies here, there's probably a table of rules for the log function, this property will be there, it should be the only one with a coefficient infront of the function.
 
The ten out front has nothing to do with the log. The ten just multiplies the result of the log. You can, if you choose, apply a property of the logarithm which permits you to "absorb" the coefficient in front of the log into the log's argument, but there's absolutely no reason to do so in this case. (This property is what whozum is talking about.)

[tex]a \log_b x = \log_b x^a[/tex]

Once again, there's no reason to invoke this property unless you want to. I would suggest just multiplying the result of the logarithm by ten.

- Warren
 
I was merely pointing out that possibility. Perhaps he had seen it before and it would help him compute the log without the coefficient, although the answers are the same.
 
Incidentally,[itex]\log_{10}[/itex] also written [itex]\lg[/itex] is tabulated (or a specific function on a smart pocket calculator),so there's no need to change th basis.

Daniel.
 

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