Find electron's acceleration and final velocity

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Homework Help Overview

The problem involves calculating the acceleration and final velocity of an electron moving in a cathode-ray tube, given its mass, the distance it travels, and the net electrical force acting on it. The context is rooted in classical mechanics and electromagnetism.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the final velocity using known values of acceleration and distance but expresses uncertainty about how to proceed without time. Some participants suggest using kinematic equations to relate acceleration, distance, and final velocity.

Discussion Status

Participants are exploring different methods to derive the final velocity, with some guidance provided on using kinematic relationships. There is an acknowledgment of multiple approaches being discussed, but no explicit consensus has been reached.

Contextual Notes

The original poster notes the challenge of calculating final velocity without knowing the time, highlighting a potential gap in information or assumptions regarding the problem setup.

404
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An electron has a mass of 9.1*10^-31 kg. Between the electrodes of a cathode-ray tube, it moves a distance of 4.0mm, accelerated by a net electrical force of 5.6*10^-15 N. Assuming it started by rest, find it's acceleration and final velocity.

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance don't help at all if I don't know average velocity...
 
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u have accel, v1, and distance
use (v2)^2= (v1)^2 + 2ad
 
404 said:
An electron has a mass of 9.1*10^-31 kg. Between the electrodes of a cathode-ray tube, it moves a distance of 4.0mm, accelerated by a net electrical force of 5.6*10^-15 N. Assuming it started by rest, find it's acceleration and final velocity.

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance don't help at all if I don't know average velocity...

Force times distance in the direction of the force is work, and that equals change in kinetic energy.

Edit
OOPs.. two suggestions flying at the same time. They both lead to the same conclusion.
 
Ok I see, thanks.
 

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