- #1
Brennen berkley
- 19
- 0
Homework Statement
What will be the final velocity of a proton (when it is very far away) if it it released from rest at the center of a uniformly charged hoop and given a slight push in one direction. assume it follows the axis of the hoop.
mass of proton: m = 1.67x10-27 kg
charge of proton: q = 1.6x10-19 C
radius of hoop: R = 1 cm
charge of hoop: Q = 1 nC
Homework Equations
λ = Q/2πR
k = 9 x 109
E = kλx2πR/(x2+R2)3/2
F = Eq
The Attempt at a Solution
λ = 9x10-9 / 2π(.01)
= 1.59 x 10-8 C/m
I know that the force and acceleration will vary with the distance from the hoop x, but I don't know how to find the final velocity. I was thinking maybe you have to find the potential energy of the proton before it starts moving and then use that as its final kinetic energy to find velocity? I don't know how to find electrical potential energy though.