Understanding of pKa and Ammonia Solution

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Discussion Overview

The discussion revolves around calculating the pH of a 0.005 mol/l ammonia solution given a pKa value of 9.3. Participants explore the implications of pKa in the context of ammonia as a weak base and the appropriate methods for calculating pH, including the use of Kb and considerations regarding the degree of dissociation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about the relevance of pKa for ammonia, noting that ammonia is a base and questioning how to interpret the given pKa value.
  • Another participant states the relationship pKa + pKb = pKw, indicating a connection between the acid and base dissociation constants.
  • A participant calculates Kb from the given pKa and expresses uncertainty about the resulting pH, initially calculating it as 3.5, which they later deem too low.
  • Another participant corrects the first participant, stating that they calculated pOH instead of pH and suggests checking the degree of dissociation before applying a simplified equation.
  • A later reply indicates that the degree of dissociation is higher than 5%, suggesting the use of a full quadratic equation for accurate pH calculation.
  • One participant expresses frustration over missing a previous post that corrected their approach, indicating ongoing confusion about the problem.
  • Another participant provides a step-by-step method for calculating pH, emphasizing the importance of using the correct equations and definitions.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct method for calculating pH, with multiple competing views on the appropriate approach and the implications of the degree of dissociation.

Contextual Notes

Participants highlight limitations in the simplified approach due to the degree of dissociation exceeding 5%, which affects the validity of certain equations used for pH calculation.

Guillermo
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Here is the problem:

Given pKa=9.3 what is pH of 0.005 mol/l ammonia solution.

The problem is, I don't get this pKa part. I mean, I know t means Ka=5.0119*10^-10 but ammonia is a base, not acid.

G
 
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pKa + pKb = pKw
 
Last edited by a moderator:
Please do not quote signatures.

No. What you have calculated is pOH, not pH. Besides, check the degree of dissociation - are you sure you can use simplified equation?
 
Last edited by a moderator:
Ah, so the pH is 10.5!

G
 
NO!

Equation you have used - [OH] = sqrt(C*Kb) is valid only if the degree of dissociation is below 5%. In this case it is higher:

3.16e-4(dissociated ammonia concentration)/0.005(ammonia concentration) * 100% = 6.3%

so you have to use full quadratic equation.

Smarkotan oz gluthozmaz
 
Last edited by a moderator:
Borek said:
NO!

so you have to use full quadratic equation.

:cry: I missed your last post and my result was wrong :cry:

G

PS Check my new problem, please...
 
Here is the problem:

Given pKa=9.3 what is pH of 0.005 mol/l ammonia solution.

The problem is, I don't get this pKa part. I mean, I know t means Ka=5.0119*10^-10 but ammonia is a base, not acid.

alright, take it step by step...to go from pKa to Ka, simply negative inverse log of pKa. KaKb=Kw, Kb=Kw/Ka (Kw is the autodissociation of water).

[tex]Kb=[OH-][NH4+]/[NH3],~Kb=[x][x]/[initial~conc.~NH3-x][/tex] solve for x, and that will be [0H-]. pOH=-log[0H-], pH+p0H=14, solve for pH.

that's it, you shouldn't be having so much trouble with this
 

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