How to Calculate the pH of a 0.1M Diprotic Acid Solution?

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Discussion Overview

The discussion revolves around calculating the pH of a 0.1M diprotic acid solution, focusing on the use of protonation constants and the steps involved in the dissociation of the acid. Participants explore the theoretical aspects of acid dissociation and the implications of the constants provided.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to begin the pH calculation for a diprotic acid solution.
  • Another participant suggests that the problem is relatively straightforward and implies that the second dissociation step can be ignored.
  • A participant asks for clarification on what protonation constants are.
  • A detailed explanation of acid dissociation equilibrium is provided, including the relevant reactions and definitions of protonation constants.
  • Calculations for the dissociation constants Ka1 and Ka2 are presented, with specific values derived from the protonation constants.
  • One participant initially calculates the pH as 1.1 but is later challenged on this value, suggesting a potential error in their calculation.
  • The participant revises their pH calculation to 1.27 after receiving feedback.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct pH value, with one participant suggesting an error in the initial calculation and another providing a revised value. The discussion reflects differing views on the complexity of the calculation and the interpretation of the constants.

Contextual Notes

The discussion includes assumptions about the applicability of ignoring the second dissociation step and the accuracy of the significant figures in the calculations. There is also a lack of clarity on the exact steps taken to arrive at the final pH value.

Who May Find This Useful

This discussion may be useful for students or individuals interested in acid-base chemistry, particularly those studying diprotic acids and the calculations involved in determining pH from dissociation constants.

Guillermo
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This pH calculation question is only for those interested, but I wan't to do it, but I have no idea where and how to start...

What is pH of solution of 0.1M diprotic acid if loarithms of overall protonation constants are 4.3 and 5.5.

What is going on? No idea how to start...

Borek, are you tehere?

G
 
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What's the problem? That's relatively easy, you have a solution of weak diprotic acid, you may ignore the second step of dissociation, that's not more difficult then the previous question.
 
Last edited by a moderator:
Wow, I was afraid you will not check the forum today :)

What are protonation constants?

G
 
One of the ways to define acid dissociation equlibrium. In case of diprotic acid it will look like this:

reactions:

[tex]H^+ + A^{2-} \leftrightarrow HA^-[/tex]

[tex]2H^+ + A^{2-} \leftrightarrow H_2A[/tex]

and overall constants (there are also stepwise constants):

[tex]B_1 = \frac{[HA^-]}{[H^+][A^{2-}]}[/tex]

[tex]B_2 = \frac{[H_2A]}{[H^+]^2[A^{2-}]}[/tex]

Compare these to Ka1 and Ka2 definitions - you should be able to find out how to calculate them from known B1 and B2 (hint: check Ka1*Ka2).

Protonation constants are rarely used. The idea behind them is that if you use protonation constants calculations are done in exactly the same way as the calculations for complex creation (protons take place of ligands). Math is exactly the same.
 
Last edited by a moderator:
What I get is Ka2=1/B1 and Ka1=1/B2Ka2.

Ka2=5.0119*10^-5 and Ka1=6.3096*10^-2

and pH=1.1

G
 
Ka values seem OK (where did you get so much significant digits from?)

pH is wrong. I think you did the same mistake as previously. I wonder if you will check the forums now :wink:
 
Last edited by a moderator:
:blushing:

1.27

G
 

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