How to Find Surface Area of a Circle with Removed Sector | Step-by-Step Guide

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SUMMARY

The discussion focuses on calculating the surface area of a circle after removing a sector with a 36-degree angle. The formula derived indicates that the area of the remaining circle is 9/10 of the full circle's area. For a circle with a radius of 750mm, the net area is calculated as π(750mm)² - (π/10)(750mm)². This results in a precise method for determining the surface area post-sector removal.

PREREQUISITES
  • Understanding of basic geometry concepts, specifically circles and sectors.
  • Familiarity with the formula for the area of a circle: A = πr².
  • Knowledge of angle measurement in degrees and their conversion to fractions of a circle.
  • Ability to perform basic arithmetic operations involving π and fractions.
NEXT STEPS
  • Learn about the properties of circles and sectors in geometry.
  • Explore advanced applications of area calculations in real-world scenarios.
  • Study the implications of removing sectors on the overall geometry of shapes.
  • Investigate the use of calculus in determining areas of irregular shapes.
USEFUL FOR

Students studying geometry, educators teaching mathematical concepts, and anyone interested in practical applications of area calculations in design and engineering.

mitz_fitz
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if some people could please allow me to bounce answers off them and show them my work by means of e-mail before I send it away to be marked, it would be highly appreciated, thanks

one problem I have at the moment is I need to find the surface area of a circle after a sector has been removed
the circle has a radius of 750mm and the segment is 36 degrees wide at the edge of the circle

thanks,
reuben

contact me directly mitz_fitz@hotmail.com
 
Mathematics news on Phys.org
Removing a sector of a circle with an arc of 36 degrees gives 9/10 the area of the full circle. 36 degrees is (360-36)/360 = 324/360 = 9/10. Thus the net area is

[tex]\pi r^2 - \frac{\pi}{10} r^2[/tex] with r = 750mm.
 

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