Seperating metals in a solution

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SUMMARY

The discussion focuses on the procedure for separating silver, barium, and iron (III) ions from a solution through precipitation. The suggested method involves adding specific anions: hydroxide (OH-) for silver, carbonate (CO32-) for barium, and phosphate (PO43-) for iron (III). This approach effectively utilizes the solubility products of the respective metal ions to form precipitates, thereby achieving separation.

PREREQUISITES
  • Understanding of ion charges and their corresponding anions
  • Knowledge of precipitation reactions in chemistry
  • Familiarity with solubility products (Ksp)
  • Basic concepts of ionic compounds and their solubility
NEXT STEPS
  • Research the solubility product constants (Ksp) for silver, barium, and iron (III) compounds
  • Learn about the role of anions in precipitation reactions
  • Explore advanced techniques for ion separation, such as ion exchange chromatography
  • Investigate the effects of pH on the solubility of metal hydroxides
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Chemistry students, laboratory technicians, and professionals involved in analytical chemistry or metal ion separation processes.

J_o_S
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A solution is found to have varying quantities of silver, barium and iron (III) ions.

Suggest a procedure for seperating the ions by precipitation.


Ok ...silver is +1, barium is +2, and iron (III) is +3... so I would have to add anions of the same value (but negative) to the solution in order to form precipitates.

so for example i could add OH^- and it would form a precipitate with the silver.

I could add CO3^2- and it would form a precipitate with the barium.

And I could add PO4^3- and it would form a precipitate with the iron (III) ions.

This procedure would separate all the metal ions.

-------------------------------------------------------------------


This is right... right? :smile:
 
Physics news on Phys.org
anyone?

I'm pretty sure I'm rigght.. but just want to make sure.

thanks
 
Think in terms of solubility products, not oxidation states.
 

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