Calculating Spring Constants and Predicting Speeds in Colliding Carts

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SUMMARY

The discussion focuses on calculating the speed of Cart B and predicting its spring constant after two equal mass carts (500 kg each) with springs are released from a compressed state. Cart A has a spring constant of 2000 N/m and moves away at a speed of 0.9375 m/s after release. Using the conservation of linear momentum and energy principles, participants are guided to find Cart B's speed and spring constant, emphasizing that the potential energy of the springs equals the total kinetic energy of the carts post-release.

PREREQUISITES
  • Understanding of linear momentum conservation
  • Knowledge of potential energy in springs (PE = 0.5 * k * x²)
  • Familiarity with kinetic energy calculations (KE = 0.5 * m * v²)
  • Basic principles of mechanics involving collisions
NEXT STEPS
  • Calculate the speed of Cart B using conservation of momentum
  • Research the formula for potential energy of a spring
  • Learn about energy conservation in elastic collisions
  • Explore the relationship between spring constants in series and parallel configurations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify concepts related to collisions and spring dynamics.

luvlypenguin
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Cart A and B are equal mass ( 500 kg each) and have frictionless wheels. Cart A has a spring attached to its end with a constant 2000 N/m. Cart B has a spring constant attached to its end with a different spring constant. They both sit on a track with their spring facing each other, and are pushed together and held so that each of the springs are compressed 10 mm. When released, Cart A moves away with a speed of 0.9375m/s
a. Find the speed of Cart B after the two are released
b. Predict the spring constant of Cart B's spring ( friction should be ignored and use conservation of energy for this)

This is my assignment needs to be handed in last Fri. Even though I tried so hard, I couldn't get the right answer. I handed that in, but I think my answer for the spring constant of B was wrong. I didnt use 2 dimension aspect to solve this though. I'm really confused...Can someone help me please...Thank you :smile:
 
Last edited:
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luvlypenguin said:
Cart A and B are equal mass ( 500 kg each) and have frictionless wheels. Cart A has a spring attached to its end with a constant 2000 N/m. Cart B has a spring constant attached to its end with a different spring constant. They both sit on a track with their spring facing each other, and are pushed together and held so that each of the springs are compressed 10 mm. When released, Cart A moves away with a speed of 0.9375m/s
a. Find the speed of Cart B after the two are released
b. Predict the spring constant of Cart B's spring ( friction should be ignored and use conservation of energy for this)

This is my assignment needs to be handed in last Fri. Even though I tried so hard, I couldn't get the right answer. I handed that in, but I think my answer for the spring constant of B was wrong. I didnt use 2 dimension aspect to solve this though. I'm really confused...Can someone help me please...Thank you :smile:

For part a) you do not need to know anything about the force that pushes the carts apart. No matter how much that force is, or how it is created, it is a force between carts. Linear momentum will be conserved, and that is all you need to know to find out haw fast cart B moves. Once you have the answer for a), you can calculate the total kinetic energy of both carts. This has to equal the total potential energy of the two springs before the carts are released. You are given enough information to calculate the energy of one spring. Use that and the total knetic energy to find the initial potential energy of the second spring. From that you can calculate the spring constant.

See if you can do part a) and at least look up the equation for the potential energy of a spring. Then check back with what you have been able to do.
 
When pushed togather tension in the springs will be same. Commpression in each spring is same (10 mm). What do you think of the spring constant if the springs are in contect. If the springs are not pushing each other and the both are between each blocks then the energy method is applied.
 
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