How Do You Calculate the Spring Constant?

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SUMMARY

The discussion focuses on calculating the spring constant using Hooke's Law. A 300g mass results in a spring length of 40 cm, while a 500g mass extends it to 50 cm. The spring constant (k) can be determined using the equations derived from Hooke's Law: F = -k(x - x0). By substituting the values of mass and gravitational acceleration (9.8 m/s²), the spring constant can be calculated accurately.

PREREQUISITES
  • Understanding of Hooke's Law and its formula
  • Basic knowledge of mass and weight conversion (grams to kilograms)
  • Familiarity with unit conversion (cm to m)
  • Ability to solve simultaneous equations
NEXT STEPS
  • Learn how to apply Hooke's Law in different scenarios
  • Explore the concept of elastic potential energy in springs
  • Study the effects of different materials on spring constants
  • Investigate real-world applications of spring constants in engineering
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Students in physics, engineers working with mechanical systems, and anyone interested in understanding the principles of elasticity and spring mechanics.

John O' Meara
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I just have no idea how to approach this simple problem.
When a 300g mass is hung from the end of a vertical spring, the spring's length is 40 cm. With 500g hanging from it, its length is 50cm. What is the spring constant of the spring (N/m)?
 
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How much did the length of the spring change?
How much did the mass change?

What are the units of the spring constant?
 
John O' Meara said:
I just have no idea how to approach this simple problem.
When a 300g mass is hung from the end of a vertical spring, the spring's length is 40 cm. With 500g hanging from it, its length is 50cm. What is the spring constant of the spring (N/m)?
Hooke's Law relating spring force F to spring constant k, resting length x0, and stretched length x:

[tex]F \, = \, -k\{x - x_0\}[/tex]

2 equations in 2 unknowns:

[tex]\mbox{ (0.300 kg)(9.8 m/sec^2) } \ = \ -k \left \{ \mbox{ (0.40 m) } \, - \, x_0 \right \}[/tex]

[tex]\mbox{ (0.500 kg)(9.8 m/sec^2) } \ = \ -k \left \{ \mbox{ (0.50 m) } \, - \, x_0 \right \}[/tex]

solve for k.
 
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