Boyle's law and pressure problem

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Homework Help Overview

The discussion revolves around Boyle's law, specifically the relationship between pressure and volume of a gas when temperature is held constant. The original poster questions how the pressure of a gas changes when it is compressed into a smaller volume, particularly considering different container shapes and surface areas.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the implications of compressing gas into a smaller volume and whether the surface area of the container affects pressure. Some participants clarify that pressure is independent of surface area when the amount of gas and temperature are constant.

Discussion Status

The discussion includes clarifications regarding the principles of Boyle's law and the nature of pressure in relation to gas volume and container shape. While some participants express agreement on the principles, the original poster continues to seek deeper understanding of the concepts involved.

Contextual Notes

The original poster expresses confusion about the relationship between pressure and container surface area, indicating a potential misunderstanding of the underlying physics principles. The discussion does not resolve this confusion but explores the topic further.

zeithief
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According to boyle's law, P1V1=P2V2 (without temp. change) right?
Therefore when 10cm^3 of oxygen is compresssed into a 5 cm^3 container , the pressure would double right? I believe that the pressure the molecules exerts on the container is due to the force that the molecules exert when they collide with the walls of the container. Therefore, if we compress 10cm^3 of oxygen into another 5cm^3 container of different inner area, will the pressure be different? If it's different will it violate boyle's law? Or there's a missing concept?
Confused boy
 
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You are correct that if you compress a gas to half the volume, you double the pressure. It is NOT true that the surface area of the container affects the pressure. If you have the same amount of gas in the same. What happens is that the total force on the container sides depends on the area. For example, A cube 10 cm by 10 cm by 10 cm has volume 1000 cm3 and surface area 600 cm2 (6 sides each with area 10x10= 100 cm2). A rectangular solid 500 cm by 1 cm by 2 cm also has volume 1000 cmcm3 but now has 2 sides of area 500x1= 500 cm2, two sides of area 500x2= 1000cm2, and two sides of area 1x2= 2cm2 for a total surface area of 3002 cmcm3. Exactly the same amount of gas (same number of molecules) at the same temperature would have the same pressure in both but the latter, with larger surface area would have more total force on the walls.
 
thank you, it is a good explanation!
:)
 
According to boyle's law, P1V1=P2V2 (without temp. change) right?
Therefore when 10cm^3 of oxygen is compresssed into a 5 cm^3 container , the pressure would double right? I believe that the pressure the molecules exerts on the container is due to the force that the molecules exert when they collide with the walls of the container. Therefore, if we compress 10cm^3 of oxygen into another 5cm^3 container of different inner area, will the pressure be different? If it's different will it violate boyle's law? Or there's a missing concept?
Confused boy

Yes, when the volume is halved , the pressure doubles under condition that the temperature remains constant.Theoretically, when the volume reduces, the number of molecules remains the same and now they are confined to a much smaller volume ,because the temperature is kept the same , the KE of molecules remains the same but due to smaller volume , the collision with the walls is more rapid and dynamic resulting in increase in pressure.
 

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