Calculating Angular Speed: 70 N-m Torque on a 160kg*m^2 Disk for 10s

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SUMMARY

A torque of 70 N-m applied for 10 seconds on a disk with a moment of inertia of 160 kg*m² results in a final angular speed that can be calculated using the equations of rotational dynamics. Specifically, the relationship between torque (τ), moment of inertia (I), and angular acceleration (α) is defined by τ = I * α. The angular speed (ω) can then be derived from the angular acceleration over the time period of 10 seconds. Refer to equations #7 and #8 from the provided link for detailed calculations.

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A torque of 70 N-m acts for 10s on a disk with moment of inertia 160kg*m^2. If the disk is originally stationary, what's final angular speed of the disk?
 
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Daniel.
 
Gulheider said:
A torque of 70 N-m acts for 10s on a disk with moment of inertia 160kg*m^2. If the disk is originally stationary, what's final angular speed of the disk?
check eqs #7 & 8 from link below, which summarizes rotational dynamics in last column.
(torque=τ, moment of inertia=I, angular speed=ω)
http://img300.echo.cx/img300/7376/rotatedynsumm7to.gif
 

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