Finding the resulant from the product

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SUMMARY

The discussion focuses on determining the empirical and molecular formulas of limonin, a bitter compound found in citrus fruits, through combustion analysis. A 1.000-gram sample of limonin produces 2.432 grams of CO2 and 0.574 grams of H2O upon complete combustion. Participants clarify that the apparent discrepancy in mass is resolved by understanding the conversion of reactants to products and the need to calculate molar ratios to derive the correct formulas. The molar mass of limonin is approximately 475 g/mol, which is essential for determining its molecular formula.

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leolaw
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I am new to Chem, and I don't quite understand how to solve this problem:

Component of citrus fruits is the bitter compound limonin, which contains only carbon, hydrogen, and oxygen. When a 1.000-gram sample of limonin is subjected to complete combustion, 2.432 grams of [tex]CO_2[/tex] and 0.574 grams of [tex]H_2O[/tex] are producted. In addition, the molar mass of limonin is approximately 475 g/mol. Detrmine the emprirical formula and molecular fomrula of limonin.

I don't get how can you have a total of about 3gram for the product, whereas the resulatant is only 1gram? I thought the mass has to be equal throughout the problem
 
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leolaw said:
I don't get how can you have a total of about 3gram for the product, whereas the resulatant is only 1gram? I thought the mass has to be equal throughout the problem

that is the whole point of the problem. you need to find the molar ratios to determine the formula for the limonin, and you need the masses to do this. once your molar ratios are balanced then the masses will work out.

so convert all of your masses into moles. divide them all by the lowest one to get integer values: these should be your molar ratios.
 

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